The answer is Sensitivity
Tahir can restrict actions a recipient can take on the messages he sends. It is recommended that you use IRM (Information Rights Management) if available. Choosing the private option will restrict the recipient from taking actions such as forwarding a confidential message to another person. When Tahir selects the private option, the recipient of the message will see a “please treat this as private” in the information bar.
Answer:
The answer to this question is option b which is data re-engineering.
Explanation:
In computer science, data re-engineering is a part of the software development life cycle(SDLC). In the SDLC the data re-engineering is a technique that provides the facility to increase the size of the data formats, design,data-view, etc. It is also known as the software development process in this process, there are seven-stage for software development. If we want to upgrade the software to use the data re-engineering technique so we used the software development process. We use only this process to develop the software because there is no other process to development. So the correct answer is data re-engineering
<h2>
Answer:</h2>
Option D: All of above.
is the correct answer.
<h2>
Explanation:</h2>
Risk of Collision can be defined as a chance when two different bodies start bearing same position after some time of following some courses/situations.
In order to determine risk of collision, many procedures are used. Some of them include procedures like Long-range radar scanning, Systematic observation of objects detected by radar and watching the compass bearing of an approaching vessel are used.
According to Rule 7 (Risk of Collision):
All accessible sources that are right according to the faced circumstances shall be used for each vessel so that the collision risks (if any) are determined easily.
<h2>I hope it will help you!</h2>
Answer:
public boolean equals(Object other)
{
// check correct instance
if (other instanceof IntTree)
{
try
{
IntTree otherTree = (IntTree) other;
return equals(overallRoot, otherTree.overallRoot);
}
// caught exceptions
catch (Exception e)
{
return false;
}
}
return false;
}
public boolean equals(IntTreeNode tree1, IntTreeNode tree2)
{
// if reach ends
if (tree1 == null && tree2 == null)
{
// they are equal
return true;
}
else if (tree1 == null || tree2 == null)
{
// not equal
return false;
}
// check left part
boolean leftPart = equals(tree1.left, tree2.left);
// check current element is same
boolean currentPart = tree1.element.equals(tree2.element);
// check right part
boolean rightPart = equals(tree1.right, tree2.right);
// all are equal
return (leftPart && currentPart && rightPart);
}
Explanation: