2 KOH(aq) + H2C2O4(s) → K2C2O4(aq) + 2 H2O(l) When a sample of oxalic acid (H2C2O4), which is a diprotic acid (both H-atoms are acidic), is titrated with 0.250 M potassium hydroxide solution, 24.66 mL of the potassium hydroxide solution are required to neutralize the acid. I don’t know is this gonna help but ok ._.
Answer:
P = 741.7 Pa
Explanation:
Pressure:
It is the force applied on object per unit area. The force is applied perpendicular to the surface.
Mathematical expression:
P = F/A
P = pressure
F = force
A = area
Given data:
Weight = 178 N
Area = 10 cm × 24 cm
Pressure = ?
Solution:
Area = 10 cm × 24 cm
Area = 240 cm²
Area = 240 /10000 = 0.024 m²
Formula:
P = F/A
P = 178 N / 0.024 m²
P = 741.7 Nm⁻²
Nm⁻² = Pa
P = 741.7 Pa
Answer:

Explanation:
We are given the mass of two reactants, so this is a limiting reactant problem.
We know that we will need mases, moles, and molar masses, so, let's assemble all the data in one place, with molar masses above the formulas and masses below them.
M_r: 17.03 32.00 18.02
4NH₃ + 5O₂ ⟶ 4NO + 6H₂O
m/g: 70.1 70.1
Step 1. Calculate the moles of each reactant

Step 2. Identify the limiting reactant
Calculate the moles of H₂O we can obtain from each reactant.
From NH₃:
The molar ratio of H₂O:NH₃ is 6:4.

From O₂:
The molar ratio of H₂O:O₂ is 6:5.

O₂ is the limiting reactant because it gives the smaller amount of H₂O.
Step 3. Calculate the theoretical yield.

Answer:
Solve the following problems (assuming constant temperature). Assume all numbers are 3 sig figs. 1. A sample of oxygen gas occupies a volume of 250 mL at 740 torr pressure. ... the gas exert if the volume was decreased to 2.00 liters? ... A 175 mL sample of neon had its pressure changed from 75.0 kPa to 150 kPa.
Explanation:
NH3 has 1 Nitrogen atom and 3 hydrogen atoms.