Ask question

Ask question

All categories

mrs_skeptik [129]

3 years ago

14

Which of the following statements about tornadoes is false?

2 answers:

loris [4]3 years ago

4 0

The answer is A because the time wouldn't affect the weather that much depending on the circumstances.

Rainbow [258]3 years ago

4 0

Answer:

A

Explanation:

You might be interested in

What kind of exercise does not require the use of oxygen to metabolize energy? strength aerobic stretching anaerobic

MatroZZZ [7]

Answer:

See Below

Explanation:

'an aerobic ' means it does not use oxygen

7 0

2 years ago

Write the full symbol for the isotope of oxygen having 8 neutrons.

Helen [10]

Answer:

Isotopes are forms of a chemical element that have the same atomic number but differ in mass. 16O → 8 protons + 8 neutrons; a “light” oxygen); The relative amounts are expressed as either 18O/16O or δ 18O Oxygen - 18 (aka 18O → 8 protons + 10 neutrons; a “heavy” oxygen).

6 0

3 years ago

Write an equation to show how hco3− can act as a base with hs− acting as an acid.

Ne4ueva [31]

Answer: $HCO_{3}^{-}+ HS^{-}\rightleftharpoons H_{2}CO_{3} + S^2{-}$

Explanation:

According to Bronsted and Lowry an acid is a proton donor and base is a proton acceptor.

Therefore, the equation for the reaction will be as follows.

$HCO_{3}^{-}+ HS^{-}\rightleftharpoons H_{2}CO_{3} + S^2{-}$

Here, $HCO_{3}^{-}$ acts as a base as it is accepting a proton and $HS^{-}$ acts as an acid because it is donating a proton.

3 0

3 years ago

Read 2 more answers

The settling rate of particulates in air is directly proportional to the square of their diameters (Stokes’ Law), provided that

Maksim231197 [3]

Answer:

It will take 12 hours to settle out same particulate with half the diameter from same chimney.

Explanation:

The settling rate of particulates = S

Diameter of the particulate = d

$S\propto d^2$

The settling rate of one type of particulates = $S_1$

Diameter of the one type of particulate = $d_1$

The settling rate of other type of particulates = $S_2$

Diameter of the other type of particulate = $d_2=0.5d_1$

$\frac{S_1}{(d_1)^2}=\frac{S_2}{(d_2)^2}$

$\frac{S_1}{(d_1)^2}=\frac{S_2}{(0.5d_1)^2}$

$S_1=4S_2$

$S_2=\frac{S_1}{4}$

Given that settling of one type of particulate from chimney is 2 days.So settling of other type of particulate from same chimney:

$S_2=\frac{2 days}{4}=0.5 days$

1 day = 24 hours

0.5 days = 0.5 × 24 hours = 12 hours

It will take 12 hours to settle out same particulate with half the diameter from same chimney.

4 0

3 years ago

Using this balanced equation: 2 NaOH + H2SO4 —> H2O + Na2SO4

pogonyaev

Answer:

266.25g

Explanation:

8 0

3 years ago