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leonid [27]
3 years ago
11

Can you use newton in a sentence

Physics
1 answer:
sasho [114]3 years ago
8 0
Use newton<span> in a </span>sentence<span>. An engraving of Sir Isaac </span>Newton<span>. Licensed from iStockPhoto. noun. The definition of a </span>newton<span> is a unit of force in the International System of Units, or a man's name, or the name of an English mathematician, Sir Isaac </span>Newton<span>.

</span>
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A boat on a river travels downstream between 2 points 20 miles apart in 1 hour. It makes its return trip against the current and
Tamiku [17]

There are two unknown quantities that we have to find.  In order to work with them, we have to give them temporary names.  Lets call the speed of the boat ' B ', and lets call the speed of the current ' C ' .

-- "Downstream", the current is helping the boat.  The boat sails past the trees at a speed of (B + C).

(Distance) / (Speed) = Time

(20 miles) / (B + C) = 1 hour

Multiply each side by (B+C), then divide by 1 hr:  20 mi/1 hr = B + C

-- "Upstream" the boat is going against the current. It sails past the trees at a speed of (B - C).

(Distance) / (Speed) = Time

(20 miles) / (B - C) = 2.5 hours

Multiply each side by (B-C), then divide by 2.5 hr: 20 mi/2.5 hr = B - C

We're in good shape now. We have 2 equations in 2 unknowns:

<em>B + C = 20</em>

<em>B - C =  8</em>

Add the two equations, and you get 2B = 28. So B = 14 mph

Subtract the two equations and you get 2C = 12. So C = 6 mph

<em>The speed of the boat is 14 mph .</em>

<em>The speed of the current is 6 mph . </em>

4 0
4 years ago
Shown here are astronomical objects located at different distances from Earth. Rank the objects based on their distances from Ea
nevsk [136]

Answer: star on far side of Andromeda Galaxy- star on near side of Andromeda Galaxy- star on far side of Milky Way Galaxy- star near center of Milky Way Galaxy- Orion Nebula- Alpha Centauri- Pluto-The Sun

Explanation:

Andromeda is the nearest spiral galaxy to our Milky way galaxy. The star on the far side of the Andromeda galaxy would be farthest from Earth. Then, the star at the near side of the Andromeda galaxy.

The Earth along with the Sun and other planets are located in the Orion arm of the Milky way. It is about 8 kpc from the center of the Milky way. Thus, the next farthest astronomical object would be the star on the far side of the milky way and then a star near the center of the Milky way galaxy.

Orion Nebula is 1344 ly away from Earth. Alpha centauri is 4.36 ly away from earth. Pluto is about 28 AU away from Earth and Sun is 1 AU distance away.

4 0
3 years ago
Assume that, as the battery wears out, the voltage decreases at 0.03 volts per second and, as the resistor heats up, the resista
liraira [26]

Answer:

\frac{dI}{dt} =-3*10^-^4amps/sec

Explanation:

From the question we  are told that

Voltage decreases at   \frac{dv}{dt} =-0.03volts/sec

Resistance increase at \frac{dR}{dt}=0.02ohms /sec

Resistance at R=100ohms

Current at I=0.02amps

Generally the equation for ohms law is mathematically represented as

       V=IR

Therefore

       \frac{dV}{dt} =R\frac{dI}{dt} +I\frac{dR}{dt}

Generally making \frac{dI}{dt} subject of the formula in the above equation mathematically gives

       \frac{dV}{dt} =R\frac{dI}{dt} +I\frac{dR}{dt}

      R\frac{dI}{dt} = \frac{dV}{dt} -I\frac{dR}{dt}

       \frac{dI}{dt} =\frac{1}{R}  (\frac{dV}{dt} -I\frac{dR}{dt})

Therefore

       \frac{dI}{dt} =\frac{1}{100}((-0.03) -(0.02)*(0.02))

Generally it is given that the change in current is

       \frac{dI}{dt} =-3*10^-^4amps/sec

8 0
3 years ago
Light travels from medium X into medium Y. Medium Y has a higher index of refraction. Consider each statement below:(i) The ligh
ahrayia [7]

Answer:

i) FALSE,  ii) TRUE,  iii) FALSE, iv)  FALSE

Explanation:

When light (electromagnetic radiation) travels through a material medium, its speed is less than the speed of light in a vacuum. If we define the index of parts

           n = c / v

where v is the speed of light in the material medium.

The direction of the ray can be determined by the law of refraction

          n₁ sin θ₁ = n₂ sin θ₂

Let's apply these equations to our case where

          nₓ <n_y

i) The expression of the refractive index

          nₓ < n_y

         \frac{c}{v_x} = \frac{c}{n_y}

         v_y <vₓ

therefore the expression is FALSE

ii) If we use the law of refraction, the light, when passing from a medium with a lower start to another with a higher index, must approach the normal one, away from what would be the continuation of the path of the incident ray

so the expression is TRUE

iii) The speed of light is constant in all material media

the statement is FALSE

iv) light approaches normal

Let me clarify that the normal is a line perpendicular to the surface at the point of contact, not the direction of Io.

 the statement of FALSE

8 0
3 years ago
With 51 gallons of fuel in its tank, the airplane has a weight of 2390.7 pounds. What is the weight of the plane with 81 gallons
Shtirlitz [24]

Answer: 2561.7 pounds

Explanation:

If we assume the total weight of an airplane (in pounds units) as a <u>linear function</u> of the amount of fuel in its tank (in gallons) and we make a Weight vs amount of fuel graph, which resulting slope is 5.7, we can use the slope equation of the line:

m=\frac{Y-Y_{1}}{X-X_{1}}  (1)

Where:

m=5.7 is the slope of the line

Y_{1}=2390.7pounds is the airplane weight with  51 gallons of fuel in its tank (assuming we chose the Y axis for the airplane weight in the graph)

X_{1}=51gallons is the fuel in airplane's tank for a total weigth of 2390.7 pounds (assuming we chose the X axis for the a,ount of fuel in the tank in the graph)

This means we already have one point of the graph, which coordinate is:

(X_{1},Y_{1})=(51,2390.7)

Rewritting (1):

Y=m(X-X_{1})+Y_{1}  (2)

As Y is a function of X:

Y=f_{(X)}=m(X-X_{1})+Y_{1}  (3)

Substituting the known values:

f_{(X)}=5.7(X-51)+2390.7  (4)

f_{(X)}=5.7X-290.7+2390.7  (5)

f_{(X)}=5.7X+2100  (6)

Now, evaluating this function when X=81 (talking about the 81 gallons of fuel in the tank):

f_{(81)}=5.7(81)+2100  (7)

f_{(81)}=2561.7  (8)   This means the weight of the plane when it has 81 gallons of fuel in its tank is 2561.7 pounds.

3 0
3 years ago
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