What color dose red cabbage juice turn when it is mixed with lemon juice

The average distance of Enceladus from Saturn is 238,000 km; the average distance of Titan from Saturn is 1,222,000 km. How much

aleksklad [387]

Answer:

Titan takes 11.634 times longer to orbit Saturn as compared to Enceladus.

Explanation:

We have been given that the average distance of Enceladus from Saturn is 238,000 km; the average distance of Titan from Saturn is 1,222,000 km.

We will use Kepler's Law to solve our given problem.

$\frac{(T_1)^2}{(T_2)^2}=\frac{(r_1)^3}{(r_2)^3}$

Upon substituting our given values, we will get:

$\frac{(T_1)^2}{(T_2)^2}=\frac{(238,000)^3}{(1,222,000)^3}$

$\frac{(T_1)^2}{(T_2)^2}=\frac{13481272000000000}{1824793048000000000}$

$\frac{(T_1)^2}{(T_2)^2}=\frac{13481272}{1824793048}$

$\frac{(T_1)^2}{(T_2)^2}=0.0073878361246365$

Taking square root of both sides, we will get:

$\frac{T_1}{T_2}=\sqrt{0.0073878361246365}$

$\frac{T_1}{T_2}=0.0859525225030452495$

$\frac{T_2}{T_1}=\frac{1}{0.0859525225030452495}$

$\frac{T_2}{T_1}=11.634329870476699\approx 11.634$

$T_2=11.634\cdot T_1$

This implies that time period of Titan about Sturn is 11.634 times more compared to time period of Enceladus about Saturn.

So, basically Titan takes 11.634 times longer to orbit Saturn as compared to Enceladus.

8 0

3 years ago

• an object is moving with a constant velocity

noname [10]

Answer:

Becomes Zero

Explanation:

Whenever the velocity is constant, the acceleration is zero because $\triangle V$ = 0.

And in acceleration = $\frac{\triangle V}{t}$ ,if $\triangle V$ = 0 , Acceleration will also be equal to zero.

8 0

4 years ago

the specific heat of water is 4.186. suppose 100 J of heat is added to a body of water that is insulated and the temperature ros

Vesnalui [34]

C = ms
Delta H= ms* delta T
100=m*4.186*1
m=100/4.184=23.9 g

5 0

3 years ago

Read 2 more answers

ASAP PLS

Brums [2.3K]

Answer:

t=0.816 s

y=3.26 m

Explanation:

Vertical Launch

If an object is thrown vertically in free air (no friction considered), it starts to move upwards at its maximum speed and the acceleration of gravity acts to brake it. At a given time, the object stops in mid-air and starts to fall back to the launching point.

The height of the ball at any time t is given by

$\displaystyle y=vo.t-\frac{gt^2}{2}$