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3 years ago

2000 2×10 What is the answer?

Chemistry

2 answers:

Zepler [3.9K]3 years ago

6 0

Answer:

40000

Explanation:

harina [27]3 years ago

4 0

Answer: 40000

Explanation: I really hope it works for you

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Select the correct answer. A certain reaction has this form: aA bB. At a particular temperature and [A]0 = 2.00 x 10-2 Molar, co

Pie

Answer:

$\large \boxed{\text{D. 23.34 min}}$

Explanation:

1. Find the order of reaction

Use information from the graph to find the order.

If a plot of ln[A] vs time is linear, the reaction is first order and the slope = -k.

2. Find the half-life

$k = \dfrac{\ln2}{ t_{\frac{1}{2}}}\\\\k = \text{-slope} = -(-2.97 \times 10^{-2} \text{ min}^{-1}) =2.97 \times 10^{-2} \text{ min}^{-1} \\ t_{\frac{1}{2}} =\dfrac{\ln 2}{k} = \dfrac{\ln 2}{2.97 \times 10^{-2}\text{ min}^{-1}} =\textbf{23.34 min}\\\\\text{The half-life is $\large \boxed{\textbf{23.34 min}}$}$

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4 years ago

Do all electromagnetic waves travel at the same speed?

kompoz [17]

Yes but nothing can travel faster than the speed of light

6 0

3 years ago

You are using a standardized 0.1250 M solution of sodium hydroxide to determine the concentration of sulfuric acid. After pipett

Sergeu [11.5K]

Answer: Thus the concentration of the sulfuric acid is 0.1201 M

Explanation:

$H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O$

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2SO_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=2\\M_1=?\\V_1=10.00mL\\n_2=1\\M_2=0.1250M\\V_2=19.22mL$

Putting values in above equation, we get:

$2\times M_1\times 10.00=1\times 0.1250\times 19.22\\\\M_1=0.1201M$

Thus the concentration of the sulfuric acid is 0.1201

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3 years ago

Which segment represents melting?"<br> Temperature (°C)<br> Time (minutes)

zheka24 [161]

The segment that represents melting is time (minutes) and temperature.

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3 years ago

A hockey player has the puck in the corner of the rink. An opposing player muscles him aside and emerge with the puck. This situ

Scrat [10]

Explanation:

When an element is displaced by another element in a compound then it is known as a single displacement reaction.

For example, $Mg + 2HCl \rightarrow MgCl_{2} + H_{2}$ is a single displacement reaction.

Similarly when a hockey player has the puck in the corner of the rink. An opposing player muscles him aside and emerge with the puck displays that a single player is displacing a person.

Thus, we can conclude that this situation is most analogous to single displacement reaction.

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4 years ago