Answer: The mass of the gas is 18.3 g/mol.
Explanation:
To calculate the rate of diffusion of gas, we use Graham's Law.
This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:




Squaring both sides and solving for 

Hence, the molar mas of unknown gas is 18.3 g/mol.
panjang banget gua kaga ngerti
Explanation:
(a) It is known that relation between energy and mass is as follows.

where, E = energy
m = mass
c = speed of light =
m/s
As it is given that mass is
kg. So, putting the given values into the above formula as follows.

=
= 
Therefore, we can conclude that the energy produced by the reaction between one electron and one positron is
.
(b) When gamma ray photons are produced then they will have the same frequency. Relation between energy and frequency is as follows.
E =
..... (1)
where, h = plank's constant = 
= frequency
Also,
........ (2)
Hence, equating equations (1) and (2) as follows.
=
So,
= 
= 
Thus, we can conclude that the frequency is
.
Explanation:
Expression for rate of the given reaction is as follows.
Rate = k[HgCl_{2}]x [C_{2}O^{2-}_{4}]y[/tex]
Therefore, the reaction equations by putting the given values will be as follows.
............. (1)
........... (2)
............ (3)
Now, solving equations (1) and (2) we get the value of y = 2. Therefore, by solving equation (2) and (3) we get the value of x = 1.
Therefore, expression for rate of the reaction is as follows.
Rate = ![k[HgCl_{2}]x [C_{2}O^{2-}_{4}]y](https://tex.z-dn.net/?f=k%5BHgCl_%7B2%7D%5Dx%20%5BC_%7B2%7DO%5E%7B2-%7D_%7B4%7D%5Dy)
Rate = ![k [HgCl2]1 [C_{2}O^{-2}_{4}]2](https://tex.z-dn.net/?f=k%20%5BHgCl2%5D1%20%5BC_%7B2%7DO%5E%7B-2%7D_%7B4%7D%5D2)
Hence, total order = 1 + 2 = 3
According to equation (1),
k =
Thus, we can conclude that rate constant for the given reaction is
.
True. Refer to the heat equation of water