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3 years ago

Which segment represents melting?" Temperature (°C) Time (minutes)

Chemistry

1 answer:

zheka24 [161]3 years ago

4 0

The segment that represents melting is time (minutes) and temperature.

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Find all the square roots<br>225

KiRa [710]

Answer: 15

The square root of 225 is 15.

Explanation:

https://api-project-1022638073839.appspot.com/questions/how-do-you-find-the-square-root-of-1849#642333

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3 years ago

Write the chemial formula for H3PO4

rewona [7]

Phosphoric acid, also known as orthophosphoric acid or phosphoric(V) acid, is a weak acid with the chemical formula H3PO4.

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3 years ago

A sample of carbon monoxide gas is initially in a 5858 mL container. The gas is then moved to 3.29 L container at a temperature

Doss [256]

Answer:

d i took the test

Explanation:

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3 years ago

An unknown compound contains only C , H , and O . Combustion of 5.60 g of this compound produced 13.7 g CO2 and 5.60 g H2O . Wha

son4ous [18]

Answer:

Empirical formula of compound is C₄H₈O

Explanation:

Given data:

Mass of compound = 5.60 g

Mass of CO₂ = 13.7 g

Mass of H₂O = 5.60 g

Empirical formula of compound = ?

Solution:

Percentage of C:

13.7 g/5.60 g × 12/44× 100

2.45×0.273× 100 = 66.9%

Percentage of H:

5.60 g/ 5.60 g × 2.016/18 × 100

11.2%

Percentage of O:

(66.9% + 11.2%) - 100 = 21.9%

Grams atom of C , H, O

66.9/12 = 5.6

11.2 / 1.008 = 11.11

21.9 / 16 = 1.4

Atomic ratio:

C : H : O

5.6/1.4 : 11.11/1.4 : 1.4/1.4

4 : 8 : 1

Empirical formula:

C₄H₈O

7 0

4 years ago

In a test of an automobile engine 1.00 L of octane (702 g) is burned, but only 1.84 kg of carbon dioxide is produced. What is th

Reptile [31]

Answer:

The % yield of CO2 is 85.05 %

Explanation:

Step 1: Data given

Mass of octane = 702 grams

Molar mass octane = 114.23 g/mol

Mass CO2 =1.84 kg = 1840 grams

Molar mass of CO2

Step 2: The balanced equation

2C8H18 + 25O2 → 16CO2 + 18H2O

Step 3: Calculate moles of octane

Moles octane = mass octane / molar mass octane

Moles octane = 702.0 grams / 114.23 g/mol

Moles octane = 6.145 moles

Step 4: Calculate moles of CO2

For 2 moles octane we need 25 moles O2 to produce 16 moles CO2 and 18 moles H2O

For 6.145 moles octane we'll have 8*6.145 moles =49.16 moles

Step 5: Calculate mass of CO2

Mass CO2 = moles CO2 * molar mass CO2

Mass CO2 = 49.16 moles * 44.01 g/mol

Mass CO2 = 2163.5 grams

Step 6: Calculate % yield of carbon dioxide

% yield = (actual yield / theoretical yield)*100%

% yield = (1840/2163.5)*100%

% yield = 85.05 %

The % yield of CO2 is 85.05 %

4 0

3 years ago