A pot of stew is placed on a stove to heat. The temperature of the liquid reaches 170°F, and then the pot is taken off the burne
r and placed on a kitchen counter. The temperature of the air in the kitchen is 76°F. If k = 0.34, the temperature of the liquid after 7 hours will be
ºF. (Hint: Use Newton’s cooling model.)
With the given hint to be able to answer the question above, the equation for Newton's law of cooling is as follows: T(t) = T(s) + (T0 - Ts)e^-kt where T(t) is the body's temperature at any given time, Ts is the temperature of the surrounding, T0 is the initial temperature, and k is constant. Substituting the values with the given above, T(t) = 76 + (170 - 76)*e^(-0.34)(7) This gives us the answer, T(t) = 84.7 degrees F
The rate of change for function A is 2. It would originally be 2 over one but you can just simplify it down to 2. The rate of change for function B is 3. Which would also originally be 3 over 1.
