A pot of stew is placed on a stove to heat. The temperature of the liquid reaches 170°F, and then the pot is taken off the burne
r and placed on a kitchen counter. The temperature of the air in the kitchen is 76°F. If k = 0.34, the temperature of the liquid after 7 hours will be
ºF. (Hint: Use Newton’s cooling model.)
With the given hint to be able to answer the question above, the equation for Newton's law of cooling is as follows: T(t) = T(s) + (T0 - Ts)e^-kt where T(t) is the body's temperature at any given time, Ts is the temperature of the surrounding, T0 is the initial temperature, and k is constant. Substituting the values with the given above, T(t) = 76 + (170 - 76)*e^(-0.34)(7) This gives us the answer, T(t) = 84.7 degrees F
-4x - 8 > -20 Add 8 to both sides - 4x > -12 Divide both sides by -4 **When you divide by a negative you must change the direction of the inequality sign** x < 3 Letter C
