D because I learned this 2 years ago
Answer:![Q=248.011 W](https://tex.z-dn.net/?f=Q%3D248.011%20W)
Explanation:
Given
Temperature of Room ![T_{\infty }=18^{\circ}\approx 291 K](https://tex.z-dn.net/?f=T_%7B%5Cinfty%20%7D%3D18%5E%7B%5Ccirc%7D%5Capprox%20291%20K)
Area of Person ![A=1.7 m^2](https://tex.z-dn.net/?f=A%3D1.7%20m%5E2)
Temperature of skin ![T=32^{\circ}\approx 305 K](https://tex.z-dn.net/?f=T%3D32%5E%7B%5Ccirc%7D%5Capprox%20305%20K)
Heat transfer coefficient ![h=5 W/m^2.k](https://tex.z-dn.net/?f=h%3D5%20W%2Fm%5E2.k)
Emissivity of the skin and clothes ![\epsilon =0.9](https://tex.z-dn.net/?f=%5Cepsilon%20%3D0.9)
![\Delta T=32-18=14^{\circ}](https://tex.z-dn.net/?f=%5CDelta%20T%3D32-18%3D14%5E%7B%5Ccirc%7D)
Total rate of heat transfer=heat Transfer due to Radiation +heat transfer through convection
Heat transfer due radiation ![Q_1=\epsilon \sigma A(T^4-T_{\infty }^4 )](https://tex.z-dn.net/?f=Q_1%3D%5Cepsilon%20%5Csigma%20A%28T%5E4-T_%7B%5Cinfty%20%7D%5E4%20%29)
where ![\sigma =stefan-boltzman\ constant](https://tex.z-dn.net/?f=%5Csigma%20%3Dstefan-boltzman%5C%20constant)
![Q_1=0.9\times 5.687\times 10^{-8}\times 1.7\times (305^4-291^4)](https://tex.z-dn.net/?f=Q_1%3D0.9%5Ctimes%205.687%5Ctimes%2010%5E%7B-8%7D%5Ctimes%201.7%5Ctimes%20%28305%5E4-291%5E4%29%20)
![Q_1=129.01 W](https://tex.z-dn.net/?f=Q_1%3D129.01%20W)
Heat Transfer due to convection is given by
![Q_2=hA(\Delta T)](https://tex.z-dn.net/?f=Q_2%3DhA%28%5CDelta%20T%29)
![Q_2=5\times 1.7\times 14=119 W](https://tex.z-dn.net/?f=Q_2%3D5%5Ctimes%201.7%5Ctimes%2014%3D119%20W)
![Q=Q_1+Q_2](https://tex.z-dn.net/?f=Q%3DQ_1%2BQ_2)
![Q=129.01+119=248.011 W](https://tex.z-dn.net/?f=Q%3D129.01%2B119%3D248.011%20W)
Answer:
F in the definition of potential energy is the force exerted by the force field, e.g., gravity, spring force, etc. The potential energy U is equal to the work you must do against that force to move an object from the U=0 reference point to the position r.
Explanation:
Hi there!
We can use Newton's Second Law:
![\Sigma F = ma](https://tex.z-dn.net/?f=%5CSigma%20F%20%3D%20ma)
ΣF = Net force (N)
m = mass (kg)
a = acceleration (m/s²)
We can rearrange the equation to solve for the acceleration.
![a = \frac{\Sigma F}{m}\\\\a = \frac{24}{4} = \boxed{6 \frac{m}{s^2}}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B%5CSigma%20F%7D%7Bm%7D%5C%5C%5C%5Ca%20%3D%20%5Cfrac%7B24%7D%7B4%7D%20%3D%20%5Cboxed%7B6%20%5Cfrac%7Bm%7D%7Bs%5E2%7D%7D)
Answer:
It would be A, because it is has more height in which the potential energy would be greater.