corrected question:The heavyweight boxing champion of the world punches a sheet of paper in midair, bringing it from rest up to a speed of 26.5 m/s in 0.044 s . The mass of the paper is 0.003 kg. Part A Find the force of the punch on the paper
Answer:
Force=1.8N
Explanation:
Newtons third law states that in every action there is equal and opposite reaction.
The force of the punch will be the force that moves the paper by a speed of 26.5m/s.


m=0.003kg , v=26.5m/s u=0(the paper is punched from rest) t=0.044s

F=1.8N
a) It can dissolve other substances and has high specific heat capacity.
b) Pressure is transferred equally in all directions
c) F=14*0.04/0.02=28 N
d) I'd expect that it will sink cause weight will pull it to the bottom
e) Because the buoyant force is stipulated by difference between pressures in the top and bottom surfaces of a body.
f) Because this force increases in denser liquids:
, where rho is density.
g) Q=Av, where v - speed, A - area. With the same flow rate v=Q/A, so larger area decreases speed and vice versa.
If the density of water does not vary and the vents range in depth from about 1500 m to 3200 m below the surface, then the gauge pressure at a 2452-m deep vent is 224.268 atm.
Calculation:
Step-1:
It is given that the vents range in depth from about 1500 m to 3200 m below the surface. If we are assuming that the density of water does not vary. Then it is required to calculate the gauge pressure at a 2452-m deep vent.
The gauge pressure at a particular depth of ocean water is calculated as:

Here
is the density of water, P is the required pressure, h is the depth of water, and g is the gravitational acceleration.
Step-2:
Now we are substituting the values to calculate the pressure at the depth of 2452-m.

Learn more about gauge pressure here,
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The initial angular speed of the fan will be 55.0 rad/sec. The angular speed of the fan decreases to 84.7 rad/s in 2.96 s.
<h3>What is angular acceleration?</h3>
Angular acceleration is defined as the pace of change of angular velocity with reference to time.
Given data;
Final angular speed,
Initial angular speed, 
Time period,t= 2.96 s
Angular deceleration = 47.2 rad/s²

Hence the initial angular speed of the fan will be 55.0 rad/sec.
To know more about angular acceleration refer to the link ;
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Relative wind<span> is defined as the airflow relative to an airfoil.</span>