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vladimir2022 [97]
3 years ago
12

To determine the speed of a wave, you would use which of the following formulas?

Physics
2 answers:
iVinArrow [24]3 years ago
8 0

Explanation :

(a) The distance between two consecutive crests or troughs is called wavelength of a wave. It is denoted by \lambda

The number of vibrations produced per second is called its frequency. It is denoted by \nu.

We know that the distance covered per unit time is called the speed of the wave i.e.

s=\dfrac{d}{t}

The distance covered by the wave is \lambda. So,

s=\dfrac{\lambda}{T}

We know that T is the time period of the wave and the relation between the frequency and the time period is \nu=\dfrac{1}{T}

So, speed=wavelength\times frequency

So, the correct option is (b).

(b) Human ear consists of the outer ear, middle ear, and inner ear.

Middle ear amplifies the vibrations from the sound waves. It consists of three bones namely hammer, anvil and stirrup. The amplification of sound waves takes place many times by these bones.

So, the correct option is (c).

vovangra [49]3 years ago
4 0
Speed = wavelength x frequency determine the speed of a wave,
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Answer: B=0.0162T

Explanation:

let this sign be ∅ (titha in degrees)

let coefficient of friction of 0.200 be u

and i be current i= 1.41A

mass m=1.14g/cm m=0.0114g/m

To find the magnetic field from the north will be:

tan ∅= u

∅=tan^{-1}(0.200

∅=11.3°

The direction:

i L*B cos(∅)=  umg

divide both by iLcos(∅) to find B

B= \frac{umg}{iBcos(∅)}  where m=\frac{m}{L}

B= \frac{u(m/L)g}{icos(∅)}

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B=0.0162T

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3 years ago
A ball is thrown vertically down from the edge of a cliff with a speed of 4 m/s, how high is the cliff, if it took 12 s for the
Vesna [10]

Answer:

The height of the cliff from which the ball was dropped from is 224.4m.

\overline{v}={\frac{\Delta x}{\Delta t}}

Given the data in the question;

Initial velocity of the ball;

Time taken by the ball to reach the ground;

Distance or Height of the cliff from which the ball was thrown from;

To get the height of the Cliff, we use the Second Equation of Motion:

Where s is the distance or height,  is the initial velocity, t is the time and a is the acceleration. Since the ball was thrown down from a certain height (cliff), its is now under the influence of gravity. acceleration due to gravity;

Hence, the equation becomes

We substitute the given values into the equation

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3 0
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cricket20 [7]

A) It would be doubled.

Why?

To answer the question, we just need to calculate the momentum of the basketball using the following formula:

Momentum=mass*velocity\\\\Momenum=1kg*12\frac{m}{s}=12\frac{kg.m}{s}

Now, we have calculated the momentum and the result is 12 kg.m/s, what would happen to the velocity if we double the momentum? Let's calculate it!

Momentum=mass*velocity\\\\(2)*12\frac{kg.m}{s}=1kg*velocity\\\\velocity=\frac{24\frac{kg.m}{s} }{1kg} =24\frac{s}{s}

Hence, we can see that if the momentum is doubled, the velocity will be doubled too.

Have a nice day!

7 0
3 years ago
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Answer:

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8. What is the S.l unit for mass?<br> A. kg<br> B. m/s2<br> D.N<br> C. m/s
katrin2010 [14]

Answer:

the answer is kg

Explanation:

because the s.i unit for mass is kilogram

3 0
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