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3 years ago

What happens to the pressure of a gas when the volume of its container is increased at constant temperature?

Physics

1 answer:

zepelin [54]3 years ago

3 0

<h2>Pressure decreases as volume increases at constant temperature.</h2>

Hope it helps...

Good luck on your assignment

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A dog playing fetch picks up a tennis ball that has unfortunately landed on a wasps' nest and he is stung several

butalik [34]

Answer:

discrimination ig

Explanation:

6 0

3 years ago

Read 2 more answers

Hii guys!! ~ i've comeback again!! could you please help me with an assignment?? i have a couple of i know questions!! thank you

Nimfa-mama [501]

Answer:

Speed = 10.24 m/s.

Explanation:

Given the following data;

Distance = 100m

Time = 9.77

To find her speed;

Speed can be defined as distance covered per unit time. Speed is a scalar quantity and as such it has magnitude but no direction.

Mathematically, speed is given by the equation;

$Speed = \frac{distance}{time}$

Substituting into the equation, we have;

$Speed = \frac{100}{9.77}$

Speed = 10.24 meter per seconds. 

5 0

3 years ago

The initial speed of a body is 3.28 m/s. What is its speed after 2.32 s if it accelerates

Helga [31]

Final velocity = initial velocity + acceleration * time

v = u + at

v = 3.28 + 2.32 * 2.08

v = 3.28 + 4.83

v = 8.11 m/s

6 0

3 years ago

The Apollo Lunar Module was used to make the transition from the spacecraft to the moon's surface and back. Consider a similar m

lions [1.4K]

Answer:

Explanation:

a. Landing height is

H=1.3m

Velocity of lander relative to the earth is, i.e this is the initial velocity of the spacecraft

u=1.3m/s

Velocity of lander at impact, i.e final velocity is needed

v=?

The acceleration due to gravity is 0.4 times that of the one on earth,

Then, g on earth is approximately 9.81m/s²

Then, g on Mars is

g=0.4×9.81=3.924m/s²

Then using equation of motion for a free fall body

v²=u²+2gH

v²=1.3²+2×3.924×1.3

v²=1.69+10.2024

v²=11.8924

v=√11.8924

v=3.45m/s

The impact velocity of the spacecraft is 3.45m/s

b. For a lunar module, the safe velocity landing is 3m/s

v=3m/s.

Given that the initial velocity is 1.2m/s²

We already know acceleration due to gravity on Mars is g=3.924m/s²

The we need to know the maximum height to have a safe velocity of 3m/s

Then using equation of motion

v²=u²+2gH

3²=1.2²+2×3.924H

9=1.44+7.848H

9-1.44=7.848H

7.56=7.848H

H=7.56/7.848

H=0.963m

The the maximum safe landing height to obtain a final landing velocity of 3m/s is 0.963m

8 0

3 years ago

¿Cuál será la potencia de una bombilla conectada a una red de energía eléctrica de 440V, si la corriente que circula por el circ

goblinko [34]

Answer:

La potencia de la bombilla es de 1056 W.

Explanation:

La potencia de la bombilla se puede calcular usando la siguiente ecuación:

$P = I*V$

En donde:

P: es la potencia

I: es la corriente = 2,4 A

V: es la diferencia de potencial = 440 V

Entonces, la potencia es:

$P = I*V = 2,4 A*440 V = 1056 W$

Por lo tanto, la potencia de la bombilla es de 1056 W.

Espero que te sea de utilidad!

3 0

3 years ago