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3 years ago

What 3 types of metals have magnetic properties

Physics

2 answers:

TEA [102]3 years ago

7 0

Answer:

Explanation:

Three types of metals interact with magnetic fields: ferromagnetic, paramagnetic and diamagnetic metals. Ferromagnetic metals are strongly attracted to magnets; the rest are not. Magnets also attract paramagnetic metals, but very weakly. Diamagnetic metals repel the magnet, though the force is typically very weak.

satela [25.4K]3 years ago

6 0

Ferromagnetic, paramagnetic, and diamagnetic

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What is the speed of sound at the atmospheric temperature of 30°C?

12345 [234]

The parcel will undergo projectile motion, which means that it will have motion in both the horizontal and vertical direction.

First, we determine how long the parcel will fall using:

s = ut + 1/2 at²

where s will be the height, u is the initial vertical velocity of the parcel (0), t is the time of fall and a is the acceleration due to gravity.

5.5 = (0)(t) + 1/2 (9.81)(t)²

t = 1.06 seconds

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3 years ago

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You find yourself in a place that is unimaginably hot and dense. A rapidly changing gravitational field randomly warps space and

Marta_Voda [28]

You find yourself in a place that is unimaginably hot and dense. A rapidly changing gravitational field randomly warps space and time. Gripped by these huge fluctuations, you notice that there is but a single, unified force governing the universe, you are in the early universe before the Planck time.

<h3>What is Planck time?</h3>

The Planck time is approximately 10^-44 seconds. The smallest time interval, or "zeptosecond," that has so far been measured is 10^-21 seconds. A photon traveling at the speed of light would need one Planck time to traverse a distance of one Planck length.

<h3>What is Planck length?</h3>

Planck units are a set of measuring units used only in particle physics and physical cosmology. They are defined in terms of four universal physical constants in such a way that when expressed in terms of these units, these physical constants have the numerical value 1. These units are a system of natural units because its definition is based on characteristics of nature, more especially the characteristics of free space, rather than a selection of prototype object, as was the case with Max Planck's original 1899 proposal. They are pertinent to the study of unifying theories like quantum gravity.

To learn more about Plank time:

brainly.com/question/23791066

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8 0

2 years ago

A man lifts a 25.9 kg bucket from a well and does 5.92 kJ of work.The acceleration of gravity is 9.8 m/s^2 . How deep is the wel

Jet001 [13]

Answer:

The well is 23.3 m

Explanation:

As the bucket is lifted out of the well, energy in the man is being transferred to the bucket as gravitational potential energy.

Work done against gravity = mass * height * acceleration due to to gravity

W = mgh

5 920 J = 25.9 kg * h * 9.8 m/s²

h = 23.3 m

4 0

3 years ago

During a race, a runner runs at a speed of 6 m/s. 2 seconds later, she is running at a speed of 10 m/s. What is the runner’s acc

Lapatulllka [165]

Let's calculate the average acceleration. It is the rate of changing speeds. Hence, we need to calculate the difference of speeds. 10-6=4 m/s. The rate is now $\frac{4m/s}{2s} =2m/s^2$ .
In general, the formula for the mean acceleration between two times 1 and 2 is given by:
$\frac{u_2-u_1}{T}$ where v1 and v2 are the speeds at the respective points and T is the time interval between them.

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3 years ago

A bird lands on a bare copper wire carrying a current of 51

nirvana33 [79]

The resistance of the piece of wire is
$R= \frac{\rho L}{A}$
where
$\rho = 1.68 \cdot 10^{-8}\Omega m$ is the resistivity of the copper
$L=5.1 cm=0.051 m$ is the length of the piece of wire
$A=0.13 cm^2 = 0.13 \cdot 10^{-4} m^2$ is the cross sectional area of the wire
By substituting these values, we find the value of R:
$R= \frac{\rho L}{A}=6.6 \cdot 10^{-5} \Omega$

Then, by using Ohm's law, we find the potential difference between the two points of the wire:
$V=IR=(51 A)(6.6 \cdot 10^{-5} \Omega )=3.4 \cdot 10^{-3} V$

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3 years ago