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MArishka [77]
3 years ago
12

4. Compare the disturbance before and after the waves pass through the slit.

Physics
2 answers:
Rufina [12.5K]3 years ago
7 0

The waves became smaller after they hit the glasses.

I hope this helps : )

nataly862011 [7]3 years ago
3 0
Jesus, jesus is always the answer

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Describe two energy conversions that take place when you warm a cup of cocoa in a microwave oven.
vampirchik [111]
1.)the microwaves are absorbed by the water molecules in the cocoa. this causes the water molecules to vibrate very fast.

2.)this fast vibration causes the molecules to heat themselves up by means of bumping into each other (friction).
7 0
3 years ago
Read 2 more answers
The speed of light in air 1. depends only on the frequency of the light. 2. depends on both the wavelength and the frequency of
Mars2501 [29]

Answer:

2. depends on both the wavelength and frequency of light.

Explanation: Speed of light(v)=wavelength×Frequency.

∴speed of light depends on both wavelength and frequency as shown from the equation above.

7 0
3 years ago
Two velcro-covered pucks slide across the ice, collide and stick to one another. Their interaction with the ice is frictionless.
balu736 [363]

Answer:

<em>1. False</em>

<em>2. True</em>

<em>3. False</em>

<em>4. True</em>

Explanation:

<u>Conservation of Momentum</u>

According to the law of conservation of linear momentum, the total momentum of the system formed by both pucks won't change regardless of their interaction if no external forces are acting on the system.

The momentum of an object of mass ma moving at speed va is

p_a=m_a.v_a

The total momentum of both pucks at the initial condition is

p_1=m_a.v_a+m_b.v_b

Both pucks are moving to the right and puck B has twice the mass of puck A (let's call it m), thus

m_a=m

m_b=2m

We are given

v_a=6\ m/s\\v_b=2\ m/s

The total initial momentum is

p_1=6m+2(2m)=10m

At the final condition, both pucks stick together, thus the total mass is 3m and the final speed is common, thus

p_2=3m.v'

Equating the initial and final momentum

10m=3m.v'

Solving for v'

v'=10/3\ m/s=3.33\ m/s

1. Compute the initial kinetic energy:

\displaystyle K_1=\frac{1}{2}mv_a^2+\frac{1}{2}2mv_b^2

\displaystyle K_1=\frac{1}{2}m\cdot 6^2+\frac{1}{2}2m\cdot 2^2

K_1=18m+4m=22m

The final kinetic energy is

\displaystyle K_2=\frac{1}{2}mv'^2+\frac{1}{2}2mv'^2

\displaystyle K_2=\frac{1}{2}m\cdot 3.33^2+\frac{1}{2}2m\cdot 3.33^2

K_2=16.63m

As seen, part of the kinetic energy is lost in the collision, thus the statement is False

2. The initial speed of puck B was 2 m/s and the final speed was 3.33 m/s, thus it increased the speed: True

3. The initial speed of puck A was 6 m/s and the final speed was 3.33 m/s, thus it decreased the speed: False

4. The momentum is conserved since that was the initial assumption to make all the calculations. True

p_1=10m

p_2=3m.v'=3m(10/3)=10m

Proven

5 0
3 years ago
Please help with this
sertanlavr [38]

Answer:I have to say 56

Explanation: because it is going up by 8

6 0
3 years ago
The tent meteorite, found in 1897 near cape York, on the west coast of Greenland, is the largest meteorite exhibited by any muse
sweet-ann [11.9K]
Answer:
3.0883 x 10^10mg

Explanation:
1 kilogram = 1000 000 milligrams
So, 30 883 x 1000 000 = 30 883 000 000mg
6 0
3 years ago
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