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Juliette [100K]
2 years ago
6

Canada is the country (dash)of the united States

Physics
1 answer:
lana66690 [7]2 years ago
5 0

I believe it is north.

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A 300N box on a 43 degree angle.
Ksenya-84 [330]

Answer:is this a question??? I’m so confused

Explanation:

7 0
2 years ago
12)
Nataliya [291]

Answer: b

Explanation: the two pieces will repel as both have obtained a static charge.

5 0
3 years ago
A 10cm long wire is pulled along a U-shaped conducting rail in a perpendicular magnetic field. The total resistance of the wire
soldi70 [24.7K]

Answer:

a)  v=4.0m/s

b)  B=2.958T

Explanation:

From the question we are told that:

Wire Length l=10cm=>0.10m

Resistance R=0.35

Force F=1.0N

Power P=4.0W

a)

Generally the equation for Power is mathematically given by

P=Fv

Therefore

v=\frac{P}{F}

v=\frac{4.0}{1.0}

v=4.0m/s

b)

Generally the equation for Magnetic Field is mathematically given by

B=\frac{\sqrt{PR}}{vl}

B=\frac{\sqrt{4*0.35}}{4*0.10}

B=2.958T

5 0
2 years ago
Car B has the same mass as Car A but is going twice as fast. If the same constant force brings both cars to a stop, how far will
evablogger [386]

Answer:four times

Explanation:

Given

mass of both cars A and B are same suppose m

but velocity of car B is same as of car A

Suppose velocity of car A is u

Velocity of car B is 2 u

A constant force is applied on both the cars such that they come to rest by travelling certain distance

using  to find the distance traveled

where, v=final velocity

u=initial velocity

a=acceleration(offered by force)

s=displacement

final velocity is zero

For car A

0-(u)^2=2\times a\times s

s_a=\frac{u^2}{2a}------1

For car B

0-(2u)^2=2\times a\times s_b

s_b=\frac{4u^2}{2a}----2

divide 1 and 2 we get

\frac{s_a}{s_b}=\frac{1}{4}

thus s_b=4\cdot s_a

distance traveled by car B is four time of car A

7 0
3 years ago
The overhang beam is subjected to the uniform distributed load having an intensity of w = 50 kn/m. determine the maximum shear s
alex41 [277]
Given:

Uniform distributed load with an intensity of W = 50 kN / m on an overhang beam.

We need to determine the maximum shear stress developed in the beam:

τ = F/A

Assuming the area of the beam is 100 m^2 with a length of 10 m.

τ = F/A
τ = W/l
τ = 50kN/m / 10 m
τ = 5kN/m^2
τ = 5000 N/ m^2<span />
8 0
3 years ago
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