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erastovalidia [21]
3 years ago
15

Scientists can organize their obervations using

Physics
1 answer:
Nadya [2.5K]3 years ago
6 0

Answer:

Basically, scientists use hypothesis as  a supposition or proposed explanation made on the basis of limited evidence as a starting point for further investigation.

Explanation:

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Older railroad tracks in the U.S. are made of 12 m-long pieces of steel. When the tracks are laid, gaps are left between the sec
Shkiper50 [21]

Answer:

0.005 m

Explanation:

length of steel (L°) = 12 m

initial temperature (T) = 16 degrees

expected temperature (T') = 50 degrees

We can find how large the gaps should be if the track is not to buckle when the temperature is as high as 50 degrees from the formula below

ΔL = ∝L°ΔT where

  • ΔL = expansion / gap
  • ∝ = linear expansion coefficient of steel = 12x10^{-6} C^{-1}
  • L° = initial length
  • ΔT = change in temperature

ΔL = 12x10^{-6} x 12 x (50-16) = 0.005 m

3 0
4 years ago
By means of a rope whose mass is negligible, two blocks are suspended over a pulley, as the drawing shows, with m1 = 12.1 kg and
puteri [66]

Answer:

14.8 kg

Explanation:

We are given that

m_1=43.7 kg

m_2=12.1 kg

g=9.8 m/s^2

a=\frac{1}{2}(9.8)=4.9 m/s^2

We have to find the mass of the pulley.

According to question

T_2-m_2 g=m_2 a

T_2=m_2a+m_2g=m_2(a+g)=12.1(9.8+4.9)=177.87 N

T_1=m_1(g-a)=43.7(9.8-4.9)=214.13 N

Moment of inertia of pulley=I=\frac{1}{2}Mr^2

(T_2-T_1)r=I(-\alpha)=\frac{1}{2}Mr^2(\frac{-a}{r})=\frac{1}{2}Mr(-4.9)

Where \alpha=\frac{a}{r}

(177.87-214.13)=-\frac{1}{2}(4.9)M

-36.26=-\frac{1}{2}(4.9)M

M=\frac{36.26\times 2}{4.9}=14.8 kg

Hence, the mass of the pulley=14.8 kg

6 0
3 years ago
Which type of storm is measured by the fujita scale?
Serggg [28]
It's used for the intensity of a tornado
3 0
3 years ago
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In a pendulum, a continuous change occurs between kinetic and
agasfer [191]

\sf \qquad \qquad \huge \underbrace{єхplαnαtiσn}

The correct choice is ❝ A ❞

❖ whєn wє tαlk αвσut α pєndulum, ít gσєѕ thrσugh ❝ tσ αnd frσ ❞ mσtíσn, αlѕσ knσwn αѕ hαrmσníc mσtíσn. αѕ вєíng ín thє cαѕє σf α pєndulum, thєrє'ѕ α cσntínuσuѕ chαngє ín kínєtíc αnd pσtєntíαl єnєrgч.

❖ whєn thє вσв íѕ αt mєαn pσѕítíσn, ít hαѕ ítѕ mαхímum vєlσcítч, αnd thє nєt fσrcє αnd αccєlєrαtíσn αctíng σn ít íѕ zєrσ, thєrєfσrє ít hαѕ mαхímum kínєtíc єnєrgч αt thαt pαrtículαr ínѕtαnt.

❖ whєrє αѕ, íf thє вσв íѕ αt σnє σf thє єхtrєmє pσѕítíσnѕ, ítѕ vєlσcítч вєcσmєѕ zєrσ, αnd thє αccєlєrαtíσn αnd fσrcє αctíng σn ít íѕ mαхímum, ѕímcє ít hαѕ nσ vєlσcítч, thєrєfσrє ít hαѕ nσ kínєtíc єnєrgч αt thαt ínѕtαnt, thє σnlч єnєrgч ít hαѕ αt thαt tímє íѕ pσtєntíαl єnєrgч.

❖ ѕíncє thє mσvєmєnt íѕ cσntínuσuѕ, cσntínuσuѕ chαngє ín єnєrgч σccurѕ, вut thє ѕum σf вσth thє єnєgíєѕ rєmαínѕ cσnѕtαnt αt єvєrч ínѕtαnt.

\qquad \qquad\huge \dag\normalsize\sf \boxed{\underline{ǤríʍɌεαƿєr}} \: \huge \dag

3 0
3 years ago
A car traveling at an initial velocity of 12.0 m/s accelerates at a constant rate to 20.0 m/s over a time of 4.00 s. How far did
nasty-shy [4]
1 second - 32m
2 second - 84m
3 second - 156m
4 second - 248m
Hope this helps
6 0
3 years ago
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