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zloy xaker [14]
3 years ago
6

An object traveling at a 5.0 m/s East has a mass of 4.0kg. What is the magnitude of the object’s momentum?

Physics
1 answer:
Shtirlitz [24]3 years ago
6 0

Answer: p = 20 kg.m/s Eastward

Explanation: Momentum is the product of mass and velocity of the object or p= mv.

p = mv

= 4.0 kg ( 5.0 m/s)

= 20 kg.m/s Eastward

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Unpolarized light passes through two polarizers. Find the fraction of light from the first polarizer that gets through the secon
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Answer:

0.5

Explanation:

Data provided in the question:

The angle between their transmission axes, θ = 60°

Now,

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I₁ = I₀cos²θ

where,

I₁ is the intensity of the transmitted light

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on rearranging, we get

\frac{I_1}{I_0}=cos²60°

or

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A hydrogen discharge lamp emits light with two prominent wavelengths: 656 nm (red) and 486 nm (blue). The light enters a flint-g
mezya [45]

Answer:

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Explanation:

Given that,

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n_{r}=1.572

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Using Snell's law,

n_{r}\sin\theta_{i}=n_{a}\sin\theta_{r}

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1.572\sin37=1\times\sin\theta_{r}

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We need to calculate the angle for blue wavelength

Using Snell's law,

n_{b}\sin\theta_{i}=n_{a}\sin\theta_{b}

Put the value into the formula

1.587\sin37=1\times\sin\theta_{b}

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Using formula of angle

\Delta \theta=\theta_{b}-\theta_{r}

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\Delta \theta=1.7^{\circ}

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