All categories

3 years ago

An object traveling at a 5.0 m/s East has a mass of 4.0kg. What is the magnitude of the object’s momentum?

Physics

1 answer:

Shtirlitz [24]3 years ago

6 0

Answer: p = 20 kg.m/s Eastward

Explanation: Momentum is the product of mass and velocity of the object or p= mv.

p = mv

= 4.0 kg ( 5.0 m/s)

= 20 kg.m/s Eastward

You might be interested in

Bart ran 5000 meters from the cops and had an average speed of 6 meters/second before he got caught. How long did he run?

atroni [7]

Answer:

thats is a long time

Explanation:

maybe 1 hour

4 0

2 years ago

Read 2 more answers

A sound is recorded at 19 decibels. What is the intensity of the sound?

sp2606 [1]

$1 \times 10^{-10.1} \mathrm{Wm}^{-2}$ is the intensity of the sound.

Answer: Option B

Explanation:

The range of sound intensity that people can recognize is so large (including 13 magnitude levels). The intensity of the weakest audible noise is called the hearing threshold. (intensity about $1 \times 10^{-12} \mathrm{Wm}^{-2}$ ). Because it is difficult to imagine numbers in such a large range, it is advisable to use a scale from 0 to 100.

This is the goal of the decibel scale (dB). Because logarithm has the property of recording a large number and returning a small number, the dB scale is based on a logarithmic scale. The scale is defined so that the hearing threshold has intensity level of sound as 0.

$\text { Intensity }(d B)=(10 d B) \times \log _{10}\left(\frac{I}{I_{0}}\right)$

Where,

I = Intensity of the sound produced

$I_{0}$ = Standard Intensity of sound of 60 decibels = $1 \times 10^{-12} \mathrm{Wm}^{-2}$

So for 19 decibels, determine I as follows,

$19 d B=(10 d B) \times \log _{10}\left(\frac{I}{1 \times 10^{-12} W m^{-2}}\right)$

$\log _{10}\left(\frac{1}{1 \times 10^{-12} \mathrm{Wm}^{-2}}\right)=\frac{19}{10}$

$\log _{10}\left(\frac{1}{1 \times 10^{-12} \mathrm{Wm}^{-2}}\right)=1.9$

When log goes to other side, express in 10 to the power of that side value,

$\left(\frac{I}{1 \times 10^{-12} W m^{-2}}\right)=10^{1.9}$

$I=1 \times 10^{-12} \mathrm{Wm}^{-2} \times 10^{1.9}=1 \times 10^{-12-1.9}=1 \times 10^{-10.1} \mathrm{Wm}^{-2}$

5 0

3 years ago

When must a psychological researcher debrief human test subjects?

myrzilka [38]

Psychological researchers must debrief human test subjects at the end of every experiment.

The current code of ethics in psychological research states that researchers absolutely must debrief human test subjects at the end of every study regardless or whether or not harm or deception was involved.

Debriefing a subject after a study is an essential opportunity for the researcher to explain the purpose and aim of the study to the subject, make sure the subject is not harmed or mentally disturbed, clarify why deception was used (if deception was involved) and overall, to clarify any questions or doubts the subject might have.

3 0

3 years ago

Which element could not form in the sun and would have to be formed in a supernova?

Nimfa-mama [501]

Uranium (atomic number 92)

3 0

3 years ago

Use the values provided to calculate the initial voltage

EleoNora [17]

Answer: V1= 360 V

Explanation:

7 0

3 years ago

Read 2 more answers