1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Zinaida [17]
3 years ago
14

2. A pebble is dropped down a well and hits the water 1.5 s later. Using the equations for motion with constant acceleration, de

termine the distance from the edge of the well to the water's surface.​
Physics
1 answer:
kow [346]3 years ago
3 0

Answer:

S = 11.025 m

Explanation:

Given,

The time taken by the pebble to hit the water surface is, t = 1.5 s

Acceleration due to gravity, g = 9.8 m/s²

Using the II equations of motion

                          S = ut + 1/2 gt²

Here u is the initial velocity of the pebble. Since it is free-fall, the initial velocity

                                u = 0

Therefore, the equation becomes

                            S = 1/2 gt²

Substituting the given values in the above equation

                              S = 0.5 x 9.8 x 1.5²

                                 = 11.025 m

Hence, the distance from the edge of the well to the water's surface is, S = 11.025 m

You might be interested in
What occurs when two Stars collide into each other?
ddd [48]

Answer:

A stellar collision.

Explanation:

A stellar collision is the coming together of two stars caused by stellar dynamics within a star cluster, or by the orbital decay of a binary star due to stellar mass loss or gravitational radiation, or by other mechanisms not yet well understood.

5 0
3 years ago
Read 2 more answers
Biologists use optical tweezers to manipulate micron-sized objects using a beam of light. In this technique, a laser beam is foc
vekshin1

Answer:

Explanation:

Part A) Using

light intensity I= P/A

A= Area= π (Radius)^2= π((0.67*10^-6m)/(2))^2= 1.12*10^-13 m^2

Radius= Diameter/2

P= power= 10*10^-3=0.01 W

light intensity I= 0.01/(1.12*10^-13)= 9*10^10 W/m^2

Part B)  Using

I=c*ε*E^2/2

rearrange to solve for E= \sqrt{((I*2)/(c*ε))

c is the speed of light which is 3*10^8 m/s^2

ε=permittivity of free space or dielectric constant= 8.85* 10^-12 F⋅m−1

I= the already solved light intensity= 8.85*10^10 W/m^2

amplitude of the electric field E= \sqrt{(9*10^10 W/m^2)*(2) / (3*10^8 m/s^2)*(8.85* 10^-12 F⋅m−1)

---> E= \sqrt{(1.8*10^11) / (2.66*10^-3) = \sqrt{(6.8*10^13) = 8.25*10^6 V/m    

 

8 0
3 years ago
How can i tell the difference between a one element and another?
dybincka [34]


Normally, the number of electrons is equal to the number of protons, which makes atoms electrically neutral. The number of protons in an atom is the defining feature of an atom. It's what makes one element different from another

HOPE THIS HELPS!!!

8 0
3 years ago
Read 2 more answers
Name the material used to transfer of charges from one body to other​
Evgesh-ka [11]

Answer:

conductor

Explanation:

A "conductor" is a material that allows the charges to pass freely from one body to the other. This causes a movement among the electrons and this means that<em> the charge will be passed entirely to the object receiving it.</em> This is also called <em>"conductive material."</em>

Examples of conductors are: <em>copper, aluminum, gold, silver, seawater, etc.</em>

The opposite of conductors are called "insulators." These do not allow the free movement of charges from one object to the other.

Examples of insulators: <em>plastic, rubber, paper, glass, wool, dry air, etc.</em>

6 0
3 years ago
A mass of 13kg stretches a spring 14cm. The mass is acted on by an external force of 6sin(t/2)N and moves in a medium that impar
m_a_m_a [10]

Answer:

13u\prime\prime+33.33u\prime+910u=6sin\frac{t}{2}, \ u(0)=0,u\prime(0)=0.04\\

#Where u is in meters and t in seconds.

Explanation:

Given that :m=13.0kg, \ L=0.14m, \ F(t)=6sin\frac{t}{2}N, F_d(t*)=-4N^{-1}, u\prime(t*)=0.12m/s\\u(0)=0,u\prime(0)=0.04m/s

From \omega=kL we have:

k=\frac{\omega}{L}=\frac{mg}{0.14m}=\frac{13.0\times 9.8m/s}{0.14m}\\\\k=910kg/s^2

From F_d(t)=-\gamma u\prime(t) we have that:

\gamma=-\frac{F_d(t*)}{u\prime(t*)}=\frac{4N}{0.12m/s}\\=33.33Ns/m

Now,given that the initial value problem is given by:

13u\prime\prime+33.33u\prime+910u=6sin\frac{t}{2}, \ u(0)=0,u\prime(0)=0.04\\

Hence,the position of u at time t is given by

13u\prime\prime+33.33u\prime+910u=6sin\frac{t}{2}, \ u(0)=0,u\prime(0)=0.04\\, u in meters,t in seconds.

4 0
3 years ago
Other questions:
  • IS magnesium lactate a strong or weak electrolyte
    5·1 answer
  • If the graph shown is a position-time graph of an object moving at constant velocity, what is the velocity of the object? Assume
    8·1 answer
  • When do tornadoes form?
    13·1 answer
  • What does scientific theory mean​
    12·2 answers
  • A phone cord is 6.48 m long. The cord has a mass of 0.253 kg. A transverse wave pulse is produced by plucking one end of the tau
    6·1 answer
  • Newton's third law is sometimes summarized as "for every action, there's an equal opposite reaction" but when you jump from eart
    15·1 answer
  • 1.
    9·1 answer
  • : Assume the cell surface is not slipping along the endothelium (the velocity of the point of contact is zero with respect to a
    11·1 answer
  • What determines the strength of a base?
    5·2 answers
  • 3. A certain horizontal east-west lined wire has a mass of 0.2kg per meter of length and carries a current I. Impressed on the w
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!