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3 years ago

6

A student claims that since the three phases have different amounts of energy, molecules in substances gain or lose energy only

during phase transitions. Explain what is wrong with this student's reasoning.

2 answers:

Fofino [41]3 years ago

8 0

if heat transferred to any phase that phase has had a heat transfer

sleet_krkn [62]3 years ago

5 0

The statement is wrong because the student concluded that it is only in during phase transitions that molecules in substances gain or lose energy. It is not only on phase transition processes that energy is changed but also in other process especially chemical process where new bonds are formed while bonds are broken down.

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Un cuerpo de 480 g de masa es atraído con una fuerza de 3.9 E-6 N por otro cuerpo de 196 g de masa. Calcula la distancia a la qu

Soloha48 [4]

Answer:

La distancia entre los dos cuerpos es aproximadamente 1.269 milímetros.

Explanation:

Asumamos que ambos cuerpos son partículas, la fuerza de atracción ( $F$ ), en newtons, entre ambos cuerpos se define mediante la Ley de Newton de la Gravitación Universal, cuya ecuación es:

$F = G \cdot \frac{m_{1}\cdot m_{2}}{r^{2}}$ (1)

Donde:

$G$ - Constante de la gravitación universal, en metros cúbicos por kilogramo-segundo cuadrado.

$m_{1}, m_{2}$ - Masas de los cuerpos, en kilogramos.

$r$ - Distancia entre los cuerpos, en metros.

Si sabemos que $G = 6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}}$ , $m_{1} = 0.48\,kg$ , $m_{2} = 0.196\,kg$ y $F = 3.9\times 10^{-6}\,N$ , entonces la distancia entre los dos cuerpos es:

$r = \sqrt{\frac{G\cdot m_{1}\cdot m_{2}}{F} }$

$r \approx 1.269\times 10^{-3}\,m$

Es decir, la distancia entre los dos cuerpos es aproximadamente 1.269 milímetros.

5 0

3 years ago

Drying of Cassava (Tapioca) Root. Tapioca flour is used in many countries for bread and similar products. The flour is made by d

svet-max [94.6K]

Yea it would be 500 minus 10 is 490

5 0

3 years ago

Suppose it takes a constant force a time of 6.0 seconds to slow a 2500 kg truck

erastovalidia [21]

Answer:

$3.3\cdot 10^3\:\mathrm{N}$

Explanation:

Impulse on an object is given by $\mathrm{[impulse]}=F\Delta t$ .

However, it's also given as change in momentum (impulse-momentum theorem).

Therefore, we can set the change in momentum equal to the former formula for impulse:

$\Delta p=F\Delta t$ .

Momentum is given by $p=mv$ . Because the truck's mass is maintained, only it's velocity is changing. Since the truck is being slowed from 26.0 m/s to 18.0 m/s, it's change in velocity is 8.0 m/s. Therefore, it's change in momentum is:

$p=2500\cdot 8.0=20,000\:\mathrm{kg\cdot m/s}$ .

Now we plug in our values and solve:

$\Delta p=F\Delta t,\\F=\frac{\Delta p}{\Delta t},\\F=\frac{20,000}{6}=\fbox{$3.3\cdot 10^3\:\mathrm{N}$}$ (two significant figures).

6 0

3 years ago

A student throws a set of keys vertically upward to her sorority sister, who is in a window 3.50 m above. The second student cat

Mkey [24]

Answer:

a) 8.58 m/s upward

b) -2.211 m/s downward

Explanation:

Let gravitational acceleration g = -9.81m/s2. This is negative because it deceleration the upward motion of the key.

(a)We have the following equation of motion

$s = v_0t + gt^2/2$

where $v_0$ is the initial upward velocity of the keys, t = 1.1s is the time it takes for the keys to travel a distance of s = 3.5 m

$3.5 = v_01.1 - 9.81*1.1^2/2$

$3.5 = 1.1v_0 - 5.94$

$1.1v_0 = 3.5 + 5.94 = 9.44$

$v_0 = 9.44 / 1.1 = 8.58 m/s$

So the keys were thrown initially upward with a speed of 8.58 m/s

(b) If the initial velocity of the key is 8.58 m/s and it is subjected to a deceleration of 9.81m/s2 for 1.1s then the velocity right at the 1.1s instant is

$v = v_0 + gt = 8.58 - 9.81*1.1 = -2.211 m/s$

So they keys would have a downward speed of 2.211 m/s

5 0

3 years ago

what is the energy required to melt down a 12,400g Gold bar assuming its temperature goes from 23c to 1,064c

sergejj [24]

1665183.6J

Explanation:

Given parameters:

Mass of Gold = 12400g

Initial temperature = 23°C

Final temperature = 1064°C

Unknown:

Energy required to melt = ?

Solution:

The amount of heat required to cause this temperature change to heat the gold bar is given as;

H = m c Ф

m is the mass of gold bar

c is the specific heat capacity of gold

Ф is the heat change

Specific heat capacity of gold = 0.129J/g°C

H = m c (Ф₂ - Ф₁)

H = 12400 x 0.129 x (1064 - 23) = 1665183.6J

learn more:

Specific heat capacity brainly.com/question/7210400

#learnwithBrainly

5 0

4 years ago