All categories

4 years ago

Where is the electric potential highest on a parallel-plate capacitor?

Physics

1 answer:

Shalnov [3]4 years ago

8 0

Answer:

So highest potential of a capacitor plate system is on positive charge plate

Explanation:

As we know that capacitor is a device which is used to store electric field energy between its two plates

So here we can say that in order to store electric field energy the two plates of capacitor will hold some charge on it.

Charge on two plates will be equal in magnitude but opposite in sign

So the plate with negative charge will be at lower potential while the plate with positive charge will be at higher potential.

So highest potential of a capacitor plate system is on positive charge plate

You might be interested in

AP PHYSICS please answer

mamaluj [8]

I think it’s d not sure

4 0

3 years ago

When asked to describe resistance you say, "It is an object's ability to

Vesnalui [34]

Accept the flow of current and is measured in ohms

8 0

3 years ago

Read 2 more answers

A hockey puck slides off the edge of a platform with an initial velocity of 20 m/s horizontally. The height of the platform abov

Rina8888 [55]

Answer:

20.96 m/s

Explanation:

Using the equations of motion

y = uᵧt + gt²/2

Since the puck slides off horizontally,

uᵧ = vertical component of the initial velocity of the puck = 0 m/s

y = vertical height of the platform = 2 m

g = 9.8 m/s²

t = time of flight of the puck = ?

2 = (0)(t) + 9.8 t²/2

4.9t² = 2

t = 0.639 s

For the horizontal component of the motion

x = uₓt + gt²/2

x = horizontal distance covered by the puck

uₓ = horizontal component of the initial velocity = 20 m/s

g = 0 m/s² as there's no acceleration component in the x-direction

t = 0.639 s

x = (20 × 0.639) + (0 × 0.639²/2) = 12.78 m

For the final velocity, we'll calculate the horizontal and vertical components

vₓ² = uₓ² + 2gx

g = 0 m/s²

vₓ = uₓ = 20 m/s

Vertical component

vᵧ² = uᵧ² + 2gy

vᵧ² = 0 + 2×9.8×2

vᵧ = 6.26 m/s

vₓ = 20 m/s, vᵧ = 6.26 m/s

Magnitude of the velocity = √(20² + 6.26²) = 20.96 m/s

4 0

3 years ago

Read 2 more answers

Red light of wavelength 633 nm from a helium-neon laser passes through a slit 0.370 mm wide. The diffraction pattern is observed

erica [24]

Answer:

Δx = 6.33 x 10⁻³ m = 6.33 mm

Explanation:

We can use the Young's Double Slit Experiment Formula here:

$\Delta x = \frac{\lambda L}{d}\\\\$

where,

Δx = distance between consecutive dark fringes = width of central bright fringe = ?

λ = wavelength of light = 633 nm = 6.33 x 10⁻⁷ m

L = distance between screen and slit = 3.7 m

d = slit width = 0.37 mm = 3.7 x 10⁻⁴ m

Therefore,

$\Delta x = \frac{(6.33\ x\ 10^{-7}\ m)(3.7\ m)}{3.7\ x \ 10^{-4}\ m}$

8 0

3 years ago

how many days does it take a team of drivers to drive a truck california and back to lansing if the drivers average 15m/s includ

malfutka [58]

4days and 12hours

Explanation:

Given parameters:

Average speed = 15m/s

Distance = 1800 miles

Unknown:

Number of days = ?

Solution:

Speed is the rate of change of distance with time;

Speed = $\frac{distance}{time}$

Since the unknown is number of days, it is a measure of time:

Time = $\frac{distance }{speed}$

The distance from California to Lansing is 1800miles. The journey takes the truck drivers to and fro. It is a two way trip;

Total distance = 1800 miles x 2 = 3600miles

We need to convert miles to meters since that is the unit we can conveniently work with;

1 mile = 1609.34m

3600 miles = 3600 x 1609.34

= 5793638m

Inputting the values in the equation:

Time = $\frac{ 5793638}{15}$ = 386242.53s

Now we need to convert to day;

In a day, = 60 x 60 x 24 = 86,400s

1 day = 86400s

Therefore;

The number of days = $\frac{386242.53}{86400}$ = 4.47days

This implies that it will take them 4 days and approximately 12 hours.

learn more:

speed brainly.com/question/10048445

#learnwithBrainly

7 0

3 years ago