Answer:
- The sequence of transformations that maps triangle XYZ onto triangle X"Y"Z" is <u>translation 5 units to the left, followed by translation 1 unit down, and relfection accross the x-axis</u>.
Explanation:
By inspection (watching the figure), you can tell that to transform the triangle XY onto triangle X"Y"Z", you must slide the former 5 units to the left, 1 unit down, and, finally, reflect it across the x-axys.
You can check that analitically
Departing from the triangle: XYZ
- <u>Translation 5 units to the left</u>: (x,y) → (x - 5, y)
- Vertex X: (-6,2) → (-6 - 5, 2) = (-11,2)
- Vertex Y: (-4, 7) → (-4 - 5, 7) = (-9,7)
- Vertex Z: (-2, 2) → (-2 -5, 2) = (-7, 2)
- <u>Translation 1 unit down</u>: (x,y) → (x, y-1)
- (-11,2) → (-11, 2 - 1) = (-11, 1)
- (-9,7) → (-9, 7 - 1) = (-9, 6)
- (-7, 2) → (-7, 2 - 1) = (-7, 1)
- <u>Reflextion accross the x-axis</u>: (x,y) → (x, -y)
- (-11, 1) → (-11, -1), which are the coordinates of vertex X"
- (-9, 6) → (-9, -6), which are the coordinates of vertex Y""
- (-7, 1) → (-7, -1), which are the coordinates of vertex Z"
Thus, in conclusion, it is proved that the sequence of transformations that maps triangle XYZ onto triangle X"Y"Z" is translation 5 units to the left, followed by translation 1 unit down, and relfection accross the x-axis.
Answer:
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Step-by-step explanation:
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Answer:
The answer is 70% if you round it.
Step-by-step explanation:
45 out of 68 is 66 but if you're rounding it the answer is 70%.
Answer:
69.92°F
Step-by-step explanation:
Given:
Initial temperature ( i.e at time, t = 0) = 40°F
Temperature of the room = 70°F
Temperature after 10 minutes ( i.e at time t = 10 ) = 48°F
Now, from Newton's law of cooling
T'(t) = k(A - T(t))
T(t) temperature after time t
T'(t) =
here, A is the room temperature
thus,
= k(70 - T)
or
= kdt
on solving the differential equation, we get
T =
............(1)
Now from the boundary conditions,
i.e at time, t = 0; T = 40°F
we get,
40 = 
or
C = 30
and,
at time, t = 10; T = 48°F
thus,
48 = 
or
k =
or
k = 0.03
Therefore,
for t = 25
from 1 we have
T = 
or
T = 70 - 0.0780
or
T = 69.92°F