2 years ago

HELP ASAP!! How can you tell if three positive numbers form a Pythagorean triple?

Mathematics

2 answers:

Advocard [28]2 years ago

8 0

The formula for the Pythagorean therom is: a[tex] a^{2} + b^{2} = c^{2}

So, If a^{2} and b^{2} add up to c^{2} than it is a Pythagorean triple.

andrey2020 [161]2 years ago

7 0

<u>Sample Response:</u> Square all three numbers. If the largest number squared is equal to the sum of the squares of the other two, then the numbers form a Pythagorean triple.

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$\dfrac{Cos \ A}{1 + Sin \ A}=\dfrac{Cos \ A *(1-Sin \ A)}{(1+Sin \ A)(1 - Sin \ A)}\\\\\\=\dfrac{Cos \ A *(1 - Sin \ A)}{1^{2}-Sin^{2} \ A}\\\\\\=\dfrac{Cos \ A *(1 - Sin \ A)}{Cos^{2} \ A}\\\\\\=\dfrac{1-Sin \ A}{Cos \ A}$ ------(I)

$LHS =\dfrac{Cos \ A}{1+Sin \ A}+\dfrac{1+Sin \ A}{Cos \ A}\\\\\\ = \dfrac{1-Sin \A}{Cos \ A}+\dfrac{1+Sin \ A}{Cos \ A} \ [from \ equation \ (I)]\\\\\\=\dfrac{1-Sin \ A + 1 - Sin \ A}{Cos \ A}\\\\=\dfrac{2}{Cos \ A}\\\\\\=2*Sec \ A = RHS$