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xeze [42]
4 years ago
5

Which mineral property is being tested below?

Chemistry
1 answer:
Annette [7]4 years ago
4 0

The answer is C. Streak

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This hypothesis concludes that the sugar dissolves faster in warm solution has to do with increased molecular motion because the combined power in the warm solution makes molecules in water to travel quicker and sucrose molecules to fluctuate faster which produced a continued evolution favors to make the connections between sucrose molecules easier to succeed. The collisions between the water molecules and the sugar molecules are at a high rate due to increased temperature.

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The change from liquid to solid, or the reverse of melting, is called
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Wen a liquid turns into solid it loses thermal energy D freezing
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Describe 2 ways of salting out proteins ​
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2 years ago
Does a chemical reaction in a closed or open best supports the law of conservation of matter
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3 years ago
The combustion of methane(CH4) produces carbon dioxide and water. Assume that 2.0 mol of CH4 burned in the presence of excess ai
harkovskaia [24]

Answer:

The answer to your question is 98.9 %

Explanation:

Data

moles of methane = CH₄ = 2.0

excess air

Percent yield = ?

mass of CO₂ = 87 g

- Balanced chemical reaction

                CH₄  +  2O₂   ⇒  CO₂  +  2H₂O

      Reactants     Elements       Products

             1                    C                   1

             4                   H                   2

             4                   O                   2

- Calculate the molar mass of CH₄

CH₄ = 12 + 4 = 16 g

- Convert the moles to mass

                     16 g of CH₄ ----------------- 1 mol

                       x                -----------------  2 moles

                       x = (2 x 16) / 1

                       x = 32 g of CH₄

-Calculate the theoretical formation of CO₂

                     16 g of CH₄ ----------------- 44 g of CO₂

                     32 g of CH₄ ----------------  x

                            x = (32 x 44) / 16

                            x = 88 g of CO₂

-Calculate the Percent yield

     Percent yield = Actual yield/Theoretical yield x 100

     Percent yield = 87/88 x 100

    Percent yield = 98.9 %

3 0
3 years ago
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