It takes the eagle 4 minutes and 20 sec to fly 3748ft. And 1 min 40 to finish the mile
The eagle travels at 892 ft per minute.
892 x 60 = 53520 ft
53520/5280 = 10.14 miles
D(t) = -4t^3 + 40t^2 + 500t = 4088
4t^3 - 40t^2 - 500t + 4088 = 0
t = 7
Therefore, the plane has flown 4088 km 7 hours after it took off.
Take the values given for domain which is the x-axis and plug then in for x to get your range which is the y-axis value
Alejandro is correct because you do not need to add another number to 76.518, as Jiro did, but you need to round it to the nearest tenth.
Glad I could help, and good luck!
Answer:
us set up the following variables:
⎧
⎪
⎪
⎪
⎪
⎨
⎪
⎪
⎪
⎪
⎩
l
Length of Rectangle (cm)
w
Width of Rectangle (cm)
A
Area of Rectangle (
c
m
2
)
t
Time (s)
We are told that:
d
l
d
t
=
8
cm/s (const), and,
d
w
d
t
=
3
cm/s (const)
The Area of the rectangle is:
A
=
l
w
Differentiating wrt
t
(using the product rule) we get;
d
A
d
t
=
(
l
)
(
d
w
d
t
)
+
(
d
l
d
t
)
(
w
)
∴
d
A
d
t
=
3
l
+
8
w
So when
l
=
20
and
w
=
10
⇒
d
A
d
t
=
3
⋅
20
+
8
⋅
10
∴
d
A
d
t
=
60
+
80
∴
d
A
d
t
=
140
cm