Question

Through (-1,3) parallel to y= 5/4x+3

Answer 1

Answer:

The equation of line with slope  $\frac{5}{4}$  and points  ( - 1 , 3 ) is y =  $\frac{5}{4}$ x +  $\frac{17}{4}$

Step-by-step explanation:

Given equation of a line as :

y = $\frac{5}{4}$ x + 3

The line equation is in the form of y = m x + c

Where m is the slope of the line

Now while comparing given line equation with standard line equation ,

So , slope of the line m = $\frac{5}{4}$

∵ Another line is passing through points ( - 1 , 3 ) , and is parallel to given line

Now if two lines are parallel then slope of both lines are equal

Let The slope of another line = M

So, M = m = $\frac{5}{4}$

∴ The equation of line with slope $\frac{5}{4}$  and passing through points ( - 1 , 3 ) is

y - $y_1$ = M × ( x -  $x_1$ )

Or, y - 3 =  × $\frac{5}{4}$  ( x + 1 )

or,  4 × (  y - 3 ) =  5 ×   ( x + 1 )

Or,  4 y - 12 = 5 x + 5

Or,  4 y = 5 x + 17

∴   y =  $\frac{5}{4}$ x +  $\frac{17}{4}$  

Hence The equation of line with slope  $\frac{5}{4}$  and points      ( - 1 , 3 ) is y =  $\frac{5}{4}$ x +  $\frac{17}{4}$   Answer