Answer:
93.32% probability that a randomly selected score will be greater than 63.7.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a randomly selected score will be greater than 63.7.
This is 1 subtracted by the pvalue of Z when X = 63.7. So



has a pvalue of 0.0668
1 - 0.0668 = 0.9332
93.32% probability that a randomly selected score will be greater than 63.7.
f(5) means to replace the x in the equation with 5.
f(5) = 8(5) - 3
f(5) = 40 - 3
f(5) = 37
The sum is 45577788999000866;33sorry
Answer:
0.375 litres
Step-by-step explanation:
Given that:
Total amount of lemonade held by pitcher = 3 litres
Number of people in which lemonade is to be given equally = 8
Amount of Lemonade received by each person will be:
Total amount of lemonade / number of persons
3 litres / 8
= 0.375 litres
Each person receives 0.375 litres of lemonade