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3 years ago

Please help, I need this answer

Mathematics

2 answers:

enyata [817]3 years ago

7 0

Answer:

To solve we need to use pythogorean theorm. So first we take the square of both giving us 25, 16. Then we add them and get 41. So the answer is squareroot of 41 and if you round you get 6.4

<h2><u>Answer: is approx. 6.4</u></h2>

Rom4ik [11]3 years ago

6 0

Answer:

6.4

Step-by-step explanation:

By the Pythagorean Theorem:

$c=\sqrt{5^2+4^2}= \\\\\sqrt{25+16}= \\\\\sqrt{41}\approx 6.4$

Hope this helps!

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F(x) = x2 + 4x – 5 is x = -2.

Likurg_2 [28]

If im correct it would be -2(2)+4(-2)-5 which is -4-8-5 which would be -17

5 0

3 years ago

The range of the function

Naily [24]

Answer:

Range: {-4, 3, 5}

Step-by-step explanation:

The range of a function includes all the set of possible output, or y-values in a given data set of a function.

Thus, the range of the function, {(2, 3), (-3, 5), (6, -4)} includes 3, 5, and -4.

This can be written as:

Range: {-4, 3, 5}

7 0

3 years ago

Part D ? Question Suppose the cylindrical water tank has a radius of 12 feet. Use this information and the equation modeling the

Wittaler [7]

The volume of the cylindrical water tank that has a length of 20 feet and a radius of 12 feet is about <u>9,048</u> cubic feet.

The correct option is option <em>d</em>;

d. 9,048

<h3>What is the volume of a solid?</h3>

The volume of a solid indicates the amount of space the solid takes at a location.

The formula for finding the volume of the cylindrical tank is presented as follows;

<em>V</em> = π·r²·L

Where;

r = The radius of the tank

L = The length of the tank

From a similar question on the website, we have;

The length of the tank, <em>L</em> = 20 feet

Therefore;

The volume of the tank, <em>V</em> = π × 12² × 20 ≈ 9048

The volume of the water tank is about <u>9,048</u> cubic feet

Learn mort about finding the volume of a solid here:

brainly.com/question/23725200

# SPJ1

8 0

10 months ago

Hi, can someone help on this?

marissa [1.9K]

Answer:

i beleive its 9 and 1 if im reading that right

Step-by-step explanation:

8 0

3 years ago

Find the minimum and maximum of f(x, y, z) = y + 4z subject to two constraints, 2x + z = 4 and x2 + y2 = 1. g

yuradex [85]

$L(x,y,z,\lambda_1,\lambda_2)=y+4z+\lambda_1(2x+z-4)+\lambda_2(x^2+y^2-1)$

$L_x=2\lambda_1+2\lambda_2 x=0\implies\lambda_1+\lambda_2x=0$
$L_y=1+2\lambda_2y=0$
$L_z=4+\lambda_1=0\implies\lambda_1=-4$
$L_{\lambda_1}=2x+z-4=0$
$L_{\lambda_2}=x^2+y^2-1=0$

$\lambda_1=-4\implies \lambda_2x=4\implies\lambda_2=\dfrac4x$
$1+2\lambda_2y=0\implies\lambda_2y=-\dfrac12\implies8y=-x$

$x^2+y^2=1\implies (-8y)^2+y^2=65y^2=1\implies y=\pm\dfrac1{\sqrt{65}}$
$y=\pm\dfrac1{\sqrt{65}}\implies x=\mp\dfrac8{\sqrt{65}}$
$2x+z=4\implies z=4\pm\dfrac{16}{\sqrt{65}}$

We have two critical points to consider: $\left(-\dfrac8{\sqrt{65}},\dfrac1{\sqrt{65}},4+\dfrac{16}{\sqrt{65}}\right)$ and $\left(\dfrac8{\sqrt{65}},-\dfrac1{\sqrt{65}},4-\dfrac{16}{\sqrt{65}}\right)$ .

At these points, we respectively have a maximum of $16+\sqrt{65}$ and a minimum of $16-\sqrt{65}$ .

6 0

3 years ago