C
Terminal velocity is the maximum velocity attainable by an object as it falls through a fluid (air is the most common example). It occurs when the sum of the drag force (Fd) and the buoyancy is equal to the downward force of gravity (FG) acting on the object.(Wikipedia)
Complete question:
The exit nozzle in a jet engine receives air at 1200 K, 150 kPa with negligible kinetic energy. The exit pressure is 80 kPa, and the process is reversible and adiabatic. Use constant specific heat at 300 K to find the exit velocity.
Answer:
The exit velocity is 629.41 m/s
Explanation:
Given;
initial temperature, T₁ = 1200K
initial pressure, P₁ = 150 kPa
final pressure, P₂ = 80 kPa
specific heat at 300 K, Cp = 1004 J/kgK
k = 1.4
Calculate final temperature;

k = 1.4

Work done is given as;

inlet velocity is negligible;

Therefore, the exit velocity is 629.41 m/s
Answer:
57.0 m
Explanation:
Given:
v₀ = 0 m/s
t = 3.41 s
a = 9.8 m/s²
Find: Δx
Δx = v₀ t + ½ at²
Δx = (0 m/s) (3.41 s) + ½ (9.8 m/s²) (3.41 s)²
Δx = 57.0 m
Answer:
Y W Z X, B
Explanation:
It wants you to figure out the correct order starting from oldest to newest.