Answer:
The radius of a chamber is 2.36 meters.
Explanation:
Given that,
The outer wall moves at a speed of 2.72 m/s.
Mass of the person, m = 75.1 kg
The person feels a force of 235 N force pressing against his back. The force acting on the person is centripetal force. It is given by the below formula :
r is the radius of a chamber
r = 2.36 meters
So, the radius of a chamber is 2.36 meters. Hence, this is the required solution.
Answer:
Rectangular path
Solution:
As per the question:
Length, a = 4 km
Height, h = 2 km
In order to minimize the cost let us denote the side of the square bottom be 'a'
Thus the area of the bottom of the square, A = 
Let the height of the bin be 'h'
Therefore the total area, 
The cost is:
C = 2sh
Volume of the box, V = 
(1)
Total cost, 
(2)
From eqn (1):
Using the above value in eqn (1):
Differentiating the above eqn w.r.t 'a':
For the required solution equating the above eqn to zero:
a = 4
Also
The path in order to minimize the cost must be a rectangle.
Tides are incredibly vital. They are controlled by the gravity of the moon pivoting the earth on a 28 day cycle, pulling the water round the world.
On the off chance that you are a mariner you require tide tables for two vital reasons. The first is that the water may not be sufficiently profound to get in and out of harbor or, say, over a sand bank, until specific times of day.
Another reason is that to spare time and power we need to cruise with the active tide on the off chance that it is going our path - to cruise against the tide can mean really going in reverse - I have seen vast cruising vessels beating to windward against the tide on the western ways to deal with the Solent going actually in reverse, (however they had forward speed through the water). Terrible arranging!
Since it is a 28 day cycle and there are 13 heaps of 28 days in a year the tides shift day by day with respect to when it is high tide and low tide, More than that we have neap tides when the highs and lows are less and spring tides when they are most prominent. These rely on upon the periods of the moon.
On the environment front they wash into and through ocean growth circulating air through the plants and ocean life and mix up silt to clean the base of the shoreline and channels and estuaries and invigorate pools that stay on the shoreline for other plant and creature life. This is one justifiable reason motivation behind why tidal hindrances will be a calamity for beach front life since this will be lost to power era. A similar thing applies to wave control and, ashore, wind control - there will be a substantial environmental cost to any maintained or pragmatic utilization of vitality that is in truth not "renewable" - we will upset a fragile adjust of nature that will do much more harm than carbon ever could (on the off chance that it was doing any harm now, which I question)
Tides are not such a great amount of checked as anticipated but rather perilous high tides can happen at the most elevated spring tide, with the twist inland and low gaseous tension - everything pushes the water advance up the shoreline and cause harm and flooding.
Answer:
(A)
Explanation:
P1 = MVcos 30
P2 = MVcos 30
️P = -2 mvcos 30
️P = - square root of 3 mv
f1 = 2mv/ ️t
force on the wall = 2
f2 = square root of 3mv/ ️t, so f1 > f2
