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ivanzaharov [21]
3 years ago
12

A falling object is said to reach a constant velocity (terminal velocity)..

Physics
1 answer:
Lana71 [14]3 years ago
3 0
C

Terminal velocity is the maximum velocity attainable by an object as it falls through a fluid (air is the most common example). It occurs when the sum of the drag force (Fd) and the buoyancy is equal to the downward force of gravity (FG) acting on the object.(Wikipedia)




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Please Help Me I will try and give extra points if I can and if you have the rest of the answers to this then please help me out
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First, you must know that the statement "<span>An object at rest tends to stay at rest. An object in motion tends to stay in motion unless acted upon by an outside force." is true, because it is the first Law of Newton or inercy law.


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Which of the following would not increase the velocity of a sound wave in air? A. lowering the humidity of the air. B. increasin
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6 0
4 years ago
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A liquid of density 1270 kg/m3 flows steadily through a pipe of varying diameter and height. At Location 1 along the pipe, the f
FinnZ [79.3K]

Answer:

{P_2}-P_1=49.99\ KPa

Explanation:

v_1=9.43\ m/s

d_1=11.7\ cm/s

d_2=17.5\ cm/s

From continuity equation

A_1v_1=A_2v_2

v_1d_1^2=v_2d_2^2

v_2=\dfrac{9.43\times 11.7^2}{17.5^2}

v_2=4.21\ m/s

\dfrac{P_1}{\rho g}+\dfrac{v_1^2}{2g}+y_1=\dfrac{P_2}{\rho g}+\dfrac{v_2^2}{2g}+y_2

{P_1}+\rho\dfrac{v_1^2}{2}+\rho y_1g={P_2}+\rho\dfrac{v_2^2}{2}+\rho y_2g

\rho\dfrac{v_1^2}{2}+\rho y_1g -\rho\dfrac{v_2^2}{2}-\rho y_2g={P_2}-P_1

1270\times \dfrac{9.43^2}{2}+1270\times 0\times 10 -1270\times\dfrac{4.21^2}{2}-1270\times 0.175\times 10={P_2}-P_1

{P_2}-P_1=49.99\ KPa

4 0
3 years ago
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