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S_A_V [24]
3 years ago
10

......................................................

Mathematics
1 answer:
crimeas [40]3 years ago
5 0

Answer:

..............................................yes

Step-by-step explanation:

lol

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This is page four what is the answer
Fittoniya [83]

Answer:

The answer is she lost 9 matches

Step-by-step explanation:

5 0
3 years ago
Please help me......<br> Change the equation 8+4y=24 into slope-intercept form
andrew11 [14]
Slope-Intercept form - y = 4
8 0
2 years ago
Sammy bought 15.3 Liters of milk. She poured the milk equally into 5 bottles. There was 0.35 liters of milk left over. Calculate
Zanzabum

Answer:

The capacity of milk in 1 bottle is 2.99 liters

Step-by-step explanation:

Let us solve the question

∵ Sammy bought 15.3 liters of milk

∵ She poured the milk equally into 5 bottles

∵ There were 0.35 liters of milk leftover

→ At first, subtract the leftover from the quantity she bought to

   find the capacity of the five bottles

∴ The capacity of the 5 bottles = 15.3 - 0.35

∴ The capacity of the 5 bottles = 14.95 liters

→ To find the capacity of each bottle divide the total capacity by 5

∴ The capacity in one bottle = 14.95 ÷ 5

∴ The capacity in one bottle = 2.99 liters

∴ The capacity of milk in 1 bottle is 2.99 liters

8 0
3 years ago
PLZ HELP ME IM DUMB BC ITS FLIPPIN 12 IN THE MORNING&gt; In a class where 65% of the students are girls, how boys are there if t
Jlenok [28]

Answer:

do percentage over whole and multiply 100 times then divide. Btw, I fel your pain. Im currently doing hw at 1:33am rn.

Step-by-step explanation:

4 0
3 years ago
in a standard casino dice game the roller wins on the first roll if he rolls a sum of 7 or 11. what is the probability of winnin
Alborosie

<u>Answer-</u>

<em>The probability of winning on the first roll is </em><em>0.22</em>

<u>Solution-</u>

As in the game of casino, two dice are rolled simultaneously.

So the sample space would be,

|S|=6^2=36

Let E be the event such that the sum of two numbers are 7, so

E = {(1,6), (2,5), (3,4), (4,3), (5,2), (6,1)}

|E|=56

\therefore P(E)=\dfrac{|E|}{|S|}=\dfrac{6}{36}

Let F be the event such that the sum of two numbers are 11, so

F = {(6,5), (5,6)}

|F|=2

\therefore P(F)=\dfrac{|F|}{|S|}=\dfrac{2}{36}

Now,

P(\text{sum is 7 or 11)}=P(E\ \cup\ F)=P(E)+P(F)=\dfrac{6}{36}+\dfrac{2}{36}=\dfrac{8}{36}=\dfrac{2}{9}=0.22

8 0
4 years ago
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