Basically just substitute
3(-2)-1-3(-2) = -6-1+6 = -1
The answer is -1.
An equation of a line parallel to y=x-6, must have the same slope.
In this equation:
y=mx+b (slope-intercept form)
m is the slope:
The slope of the equation y=x-6 is m=1 (the number beside "x").
Now we have a point (-1,5) and the slope m=1.
Point-slope form of a line:
y-y₀=m(x-x₀)
so:
y-5=1(x+1)
answer: the equation of the line in point-slope form is :
y-5=1(x+1)
And the eqution of this line in slope-intercept form is:
y=x+6
y-5=(x+1)
y=x+1+5
y=x+6
Important:
The sum of the three angles inside
every triangle is always 180°.
First, look at the left triangle alone.
Two of its angles are 46° and 58° . (46° + 58° ) = 104°
That leaves (180° - 104° ) = 76° degrees for the third angle.
The third angle in that triangle is 'x'.
x = 76° .
At the point where 'x' and 'z' come together:
'x' and 'z' are a "linear pair".
Placed side-by-side, they form a straight line.
So (x + z) = 180° .
But x = 76°.
So z = (180° - 76°). z = 104° .
Now look at the the skinny triangle on the right alone.
The angle at the top is 13°, and z = 104°.
(13° + 104°) = 117° .
That leaves (180° - 117°) = 63° for the third angle.
'y' is the third angle.
y = 63° .
Here, I've attached a picture of the triangle that accompanies this explanation.
cot = = =
Now view the triangle.
PS. Angle theta will have a coordinate of (-, +) because it is in quadrant II.
sin of the angle would be opposite/hypotenuse, so sin =
cos of the angle would be adjacent/hypotenuse, so cos =
tan of the angle would be opposite/adjacent, so tan =
