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3 years ago

PLEASE HELP

Mathematics

1 answer:

Stels [109]3 years ago

7 0

Answer:

step three is wrong

Step-by-step explanation:

just did it

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The graph of a system of equations will intersect at exactly 1 point?

andrey2020 [161]

Answer:

A system of equations can intersect at no points; this is when the lines are parallel, which means they have the same slope and different y-intercept. A system of equations can intersect at one point; this is when the lines have different slopes.

Step-by-step explanation:

4 0

3 years ago

Convert 12°34'56” to decimal degree form. Round your answer<br> to four decimal places.

Vlada [557]

Answer:

12.57555 rounded to 12.5756

Step-by-step explanation:

34'=34*1/60=0.56°

56''=56/1/3600=0.01555°

12°+0.56°+0.01555°=12.57555°

7 0

3 years ago

Read 2 more answers

1.Show that the statement p: “If x is a real number such that x3 + 4x = 0, then x is 0” is true by

Genrish500 [490]

If x is a real number such that x3 + 4x = 0 then x is 0”.Let q: x is a real number such that x3 + 4x = 0 r: x is 0.i To show that statement p is true we assume that q is true and then show that r is true.Therefore let statement q be true.∴ x2 + 4x = 0 x x2 + 4 = 0⇒ x = 0 or x2+ 4 = 0However since x is real it is 0.Thus statement r is true.Therefore the given statement is true.ii To show statement p to be true by contradiction we assume that p is not true.Let x be a real number such that x3 + 4x = 0 and let x is not 0.Therefore x3 + 4x = 0 x x2+ 4 = 0 x = 0 or x2 + 4 = 0 x = 0 orx2 = – 4However x is real. Therefore x = 0 which is a contradiction since we have assumed that x is not 0.Thus the given statement p is true.iii To prove statement p to be true by contrapositive method we assume that r is false and prove that q must be false.Here r is false implies that it is required to consider the negation of statement r.This obtains the following statement.∼r: x is not 0.It can be seen that x2 + 4 will always be positive.x ≠ 0 implies that the product of any positive real number with x is not zero.Let us consider the product of x with x2 + 4.∴ x x2 + 4 ≠ 0⇒ x3 + 4x ≠ 0This shows that statement q is not true.Thus it has been proved that∼r ⇒∼qTherefore the given statement p is true.

8 0

3 years ago

ΔDOG has coordinates D (3, 2), O (2, −4) and G (−1, −1). A translation maps point D to D' (2, 4). Find the coordinates of O' and

geniusboy [140]

Answer:

see explanation

Step-by-step explanation:

Given D(3, 2 ) → D'(2, 4 )

The x- coordinate of D' is 1 less than D and the y- coordinate of D' is 2 more than D, thus the translation rule is

(x, y ) → (x - 1, y + 2 )

Apply this rule to points O and G

O( 2, - 4 ) → O'(2 - 1, - 4 + 2 ) → O'(1, - 2 )

G(- 1, - 1 ) → G'(- 1 - 1, - 1 + 2 ) → G'(- 2, 1 )

6 0

4 years ago

Help pleasee, its past due , im sufferingggg

jeyben [28]

Answer:

-11

Step-by-step explanation:

First we plug -2 in for c

4(-2)-3=-8-3=-11

5 0

3 years ago