All categories

3 years ago

The length of a rectangle is 2 meters less than 3 times the width. The perimeter is 44

Mathematics

1 answer:

Yakvenalex [24]3 years ago

5 0

Answer:

Width of rectangle = 6 meters

Step-by-step explanation:

Let

Width of rectangle = x

Length of rectangle = 3x-2

Perimeter of rectangle = 44 meters

We need to find:

The Width of rectangle.

The formula used is:

$Perimeter\:of\:rectangle=2(Length\times Width)$

Putting values and finding value of x

$Perimeter\:of\:rectangle=2(Length\times Width)\\44=2(3x-2+x)\\44=2(4x-2)\\44=8x-4\\8x=44+4\\8x=48\\x=\frac{48}{8}\\x=6$

So, we get the value of x = 6.

We know that Width of rectangle = x = 6

So, Width of rectangle = 6 meters

You might be interested in

What are the first 3 terms in. t(n)=-2n+7

seropon [69]

Answer:

The first 3 terms of the sequence $t(n)=-2n+7$ are:

$5, 3, 1$

Step-by-step explanation:

Given the sequence

$t(n)=-2n+7$

Here $n$ represents any term number in the sequence

Determining the first term

substitute n = 1 in the sequence to determine the first term

$t(n)=-2n+7$

$t(1)=-2(1)+7$

$t(1)=-2+7$

$t(1) = 5$

Determining the 2nd term

substitute n = 2 in the sequence to determine the 2nd term

$t(n)=-2n+7$

$t(2) = -2(2) + 7$

$t(2) = -4 + 7$

$t(2) = 3$

Determining the 3rd term

substitute n = 3 in the sequence to determine the 3rd term

$t(n)=-2n+7$

$t(3) = -2(3) + 7$

$t(3) = -6 + 7$

$t(3) = 1$

Therefore, the first 3 terms of the sequence $t(n)=-2n+7$ are:

$5, 3, 1$

5 0

3 years ago

A photographer is arranging 3 puppies in a row for a photo. There is one black puppy (B), one tan puppy (T), and one white puppy

swat32

Btw, Twb, wtb, tbw, wbt,

4 0

3 years ago

Help me please

vlabodo [156]

Answer:

Step-by-step explanation:

X=8.50

y=9.50

3 0

3 years ago

Zero of the functions f(x)= x^2 + 4x+3 and why ?

slava [35]

There are two zeros: -3 and -1. This is because when you factor f(x)<span>= x^2 + 4x + 3, it becomes f(x) = (x + 3)(x + 1). In order to find the zeros, set f(x) to 0, and then solve for x for both (x + 3) and (x + 1). You can check your answer by substituting either -3 or -1 for x in the equation 0 = </span>x^2 + 4x + 3.

6 0

3 years ago

a storeroom 21 feet long, 15 feet wide, and 11 feet high was enlarged to a length of 25 feet and a width of 17 feet. how many cu

xenn [34]

<h2>1210 cubic feet</h2>

Step-by-step explanation:

Initial dimensions of the storeroom were $21\text{ }ft$ length, $15\text{ }ft$ width and $11\text{ }ft$ height.

The room is in the shape of a cuboid. Volume of a cuboid = $V=l\times b\times h$ , where $l,b,h$ are the length, width and height of the cuboid.

So, Volume of storeroom initially = $21\text{ }ft\text{ }\times15\text{ }ft\text{ }\times11\text{ }ft\text{ }=3465\text{ }ft^{3}\text{ }$

Finally, the length was increased to $25\text{ }ft$ and width to $17\text{ }ft$ .

Final volume of storeroom = $25\text{ }ft\text{ }\times 17\text{ }ft\text{ }\times 11\text{ }ft\text{ }=4675\text{ }ft^{3}\text{ }$

Increase in volume = $4675\text{ ft}^{3}-3465\text{ ft}^{3}=1210\text{ ft}^{3}$

∴ 1210 cubic feet of storage was added.

7 0

3 years ago