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PSYCHO15rus [73]
3 years ago
5

How to solve. Y=-4(x-2)squared+4

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
3 0
What do you mean, "solve"?
y = -4(x-2)² + 4 
the line is a parabol with a maximum (2;4)
it's roots are  -4(x-2)² + 4  = 0 => (x-2)² = 1 => x-2 = 1 => x = 3
                                                              => x-2 = -1 => x = 1 
symetrical axe: x = 2
is that all you need?

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The video will end at 4.20 PM (4.50 - 30 mins). So it starts at 3.15 PM and ends at 4.20 PM. So it is 1 hour and 5 minutes.
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4 years ago
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6.perimeter of the given shape above is
avanturin [10]
The answer is B.

One side is 14 feet and the other is 6. Since it is a rectangle and a rectangle has four sides, we need to take 14 and multiply it by 2. That will get us 28. Same thing apply for the other side. 6 multiplied by 2 is 12. And if we take our 2 numbers which are 28 and 12 and we add them up, our Perimeter is 40.

Hope this helps and if it does, don't be afraid to rate my answer as well as maybe give it a "Thanks"? (Or even better a "Brainliest"). And if it’s not correct, I am sorry for wasting your time, and good luck finding the correct answer :)


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3 years ago
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In a geometric sequence, a2=2, a3=16, and a4=128.
Oduvanchick [21]

Answer:

an = 1/4(8)^n-1

Step-by-step explanation:

Given the following in a geometric sequence, a2=2, a3=16, and a4=128.

nth term of a sequence = ar^n-1

a is the first term

r is the common ratio

r = a3/a2 = a4/a3

r = 16/2 = 128/16

r = 8

a2 = ar

2 = 8a

a = 2/8

a = 1/4

The nth term by substituting the parameters will be;

an = 1/4(8)^n-1

4 0
3 years ago
the circumference of a circle is a(pi) units, and the area of the circle is b(pi) square units. If a=b, what is the radius of th
xxTIMURxx [149]

Answer:

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Jeffery is playing a game with two spinners below:
Mrrafil [7]

The <em>correct answer</em> is:


{3, 4, 5, 6, 7, 8, 9, 10, 11, 12} .


Explanation:


The sample space for rolling these two spinners is:


(1, 2), (1, 4), (1, 6), (1, 8)

(2, 2), (2, 4), (2, 6), (2, 8)

(3, 2), (3, 4), (3, 6), (3, 8)

(4, 2), (4, 4), (4, 6), (4, 8)


This gives us the sums:

3, 5, 7, 9

4, 6, 8, 10

5, 7, 9, 11

6, 8, 10, 12


As a set, these are:

{3, 4, 5, 6, 7, 8, 9, 10, 11 12}

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