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2 years ago

How to solve. Y=-4(x-2)squared+4

1 answer:

3 0

What do you mean, "solve"?
y = -4(x-2)² + 4
the line is a parabol with a maximum (2;4)
it's roots are -4(x-2)² + 4 = 0 => (x-2)² = 1 => x-2 = 1 => x = 3
=> x-2 = -1 => x = 1
symetrical axe: x = 2
is that all you need?

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Please awnser thase questions for my prarice test

Vinvika [58]

Answer:

Add 5 for the first one

The 2nd one is 25 and k or 25 thousand.

Step-by-step explanation:

add 5 for the first one because 5 + 5 = 10

9 + 5 = 14 . and 13 + 5 = 18.

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For the 2nd one: 25k means 25 thousand or the Product of 25 and k.

5 0

2 years ago

What is 3 divided by 1/3?

Vlada [557]

Answer:

It will be 9

hope this helps

4 0

3 years ago

Read 2 more answers

The cost of an uber ride, y, based on miles, x is represented by y = 2/3x + 4. How much does a 21-mile ride cost ?

dangina [55]

Answer:

Step-by-step explanation:

Let the cost of the Uber ride be represented by y in dollars.

Let the number of miles that the Uber rides be represented by x.

The equation relating x and y is expressed as

y = 2/3x + 4.

This is a slope intercept form equation. The slope is 2/3 and it represents the cost per mile.

The cost of a 21 mile ride will be

Substituting x = 21 into the given equation, it becomes

y = 2/3 × 21 + 4 = 14 + 4 = 18

The 21 mile ride costs $18

Part B) The $46 ride will cost

Substituting y = 46 into the given equation, it becomes

46 = 2x/3 + 4 =

46 - 4 = 2x/3

42 = 2x/3

2x = 42 × 3 = 126

x = 126/2 = 63

The $46 ride will be 63 miles

6 0

3 years ago

If you can run 2/5 of a mile in 1/2 hour, how far can you run in 1 1/2 hours?

forsale [732]

Answer:

1 1/5 or 6/5

Step-by-step explanation:

So you get 2/5 every 1/2 hour so take the amount you have and times it by 3.

5 0

2 years ago

PLEASE HELP (30 POINTS) Solve the rational equation x/3 = x^2/x + 5 , and check for extraneous solutions.

anygoal [31]

Option C: $x=0$ and $x=\frac{5}{2}$ are the solutions.

Explanation:

The equation is $\frac{x}{3} =\frac{x^{2} }{x+5}$

We shall determine the value of x, by simplifying the equation.

$\begin{aligned} x(x+5) &=3 x^{2} \\ x^{2}+5 x &=3 x^{2} \\ 2 x^{2}-5 x &=0 \\ x(2 x-5) &=0 \end{aligned}$

Thus, $x=0$ and $x=\frac{5}{2}$ are the solutions.

Now, let us check whether the solutions are extraneous solutions.

Let us substitute $x=0$ in the original equation to check whether both sides of the equation are equal.

$\begin{aligned}&\frac{0}{3}=\frac{0^{2}}{0+5}\\&0=\frac{0}{5}\\&0=0\end{aligned}$

Thus, both sides of the equation are equal.

Hence $x=0$ is a true solution.

Now, Let us substitute $x=\frac{5}{2}$ in the original equation to check whether both sides of the equation are equal.

$\begin{aligned}\frac{\left(\frac{5}{2}\right)}{3} &=\frac{\left(\frac{5}{2}\right)^{2}}{\left(\frac{5}{2}\right)+5} \\\frac{5}{6} &=\frac{\left(\frac{25}{4}\right)}{\left(\frac{15}{2}\right)} \\\frac{5}{6} &=\frac{5}{6}\end{aligned}$

Thus, both sides of the equation are equal.

Hence, $x=\frac{5}{2}$ is a true solution.

Thus, solutions are not extraneous.

Hence, Option C is the correct answer.

8 0

3 years ago