The answer is 123
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The balloon will reach its maximum volume and it will burst.
Given:
- A weather balloon at sea level, with gas at 65.0 L volume, 745 Torr pressure, and 25C temperature.
- When the balloon was taken to an altitude at which temperature was 25C and pressure was 0.066atm its volume expanded.
- The maximum volume of the weather balloon is 835 L.
To find:
Whether the weather balloon will reach its maximum volume or not.
Solution:
The pressure of the gas in the weather balloon at sea level = 

The volume of the weather balloon at sea level = 
The temperature of the gas in the weather balloon at sea level:

The balloon rises to an altitude.
The pressure of the gas in the weather balloon at the given altitude:

The volume of the weather balloon at the given altitude = 
The temperature of the gas in the weather balloon at the given altitude:

Using the Combined gas law:

The maximum volume of the weather balloon= V = 835 L

The volume of the weather balloon at a given altitude is greater than its maximum volume which means the balloon will reach its maximum volume and it will burst.
Learn more about the combined gas law:
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Answer:
The percent composition of fluorine is 65.67%
Explanation:
Percent Composition is a measure of the amount of mass an element occupies in a compound. It is measured in percentage of mass.
That is, the percentage composition is the percentage by mass of each of the elements present in a compound.
The calculation of the percentage composition of an element is made by:

In this case, the percent composition of fluorine is:

percent composition of fluorine= 65.67%
<u><em>The percent composition of fluorine is 65.67%</em></u>
To figure this out, you need to figure out how many molecules of mgso4 you have.
If you have 1.04 moles of MgSO4, you have that many moles times avogadro's number (6.022*10^23 molecules/mole).
1.04 moles MgSO4 * (6.022*10^23 molecules MgSO4)/1 mole MgSO4 =
6.263 *10^23 molecules MgSO4
Next, there are 4 oxygen atoms per molecule of MgSO4, so we multiply the number of molecules of MgSO4 by 4 to get the number of oxygen atoms.
6.263 *10^23 molecules MgSO4 * (4 oxygen atoms/1 MgSO4 molecule) = 2.51 * 10^24 oxygen atoms in 1.04 moles of MgSO4