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Leni [432]
2 years ago
14

Which among the materials have a varying amount of components are they compounds or mixtures​

Chemistry
2 answers:
ruslelena [56]2 years ago
8 0

Answer:

Mixture Have variable composition and can be separated into component parts by physical methods. Mixtures contain more than one kind of molecule, and their properties depend on the relative amount of each component present in the mixture.

Elodia [21]2 years ago
7 0

Answer:

Matter can be broken down into two Zalo categories: pure substances and mixtures. Pure substances are further broken down into elements and compounds. Mixtures are physically combined structures that can be separated into their original components.

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ipn [44]

Answer: Benzaldahyde

Explanation: the C₆H₅- represents the substituted benzene ring and the

CHO should represent the functional group of aldehyde

8 0
3 years ago
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How many sodium atoms will create an ionic bond with sulfur?
Galina-37 [17]
Hi,

Two sodium atoms are needed to create an ionic bond with sulfur. 
5 0
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Calculate the percentage difference in the fundamental vibrational wavenumbers of 23Na35Cl and 23Na37Cl on the assumption that t
stealth61 [152]

Answer:

1.089%

Explanation:

From;

ν =1/2πc(k/meff)^1/2

Where;

ν = wave number

meff = reduced mass or effective mass

k = force constant

c= speed of light

Let

ν =1/2πc (k/meff)^1/2  vibrational wave number for 23Na35 Cl

ν' =1/2πc(k'/m'eff)^1/2 vibrational wave number for 23Na37 Cl

The between the two is obtained from;

ν' - ν /ν  = (k'/m'eff)^1/2 - (k/meff)^1/2 / (k/meff)^1/2

Therefore;

ν' - ν /ν = [meff/m'eff]^1/2 - 1

Substituting values, we have;

ν' - ν /ν = [(22.9898 * 34.9688/22.9898 + 34.9688) * (22.9898 + 36.9651/22.9898 * 36.9651)]^1/2  -1

ν' - ν /ν = -0.01089

percentage difference in the fundamental vibrational wavenumbers of 23Na35Cl and 23Na37Cl;

ν' - ν /ν * 100

|(-0.01089)|  × 100 = 1.089%

4 0
3 years ago
___ Au₂S₃ + ___ H₂ → ___ Au + ___ H₂S
Natalija [7]

Answer:

2Au₂S₃ +  6H₂ → 4Au + 6H₂S

Explanation:

Balancing:

2Au₂S₃ +  6H₂ → 4Au + 6H₂S

6 0
3 years ago
Which statement describes how the binary ionic compound cacl2 is named?
Oksi-84 [34.3K]
Calcium Chloride because it is a type 1 so the the anion ends with -ide
6 0
2 years ago
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