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Vsevolod [243]
3 years ago
8

What mass of magnesium chloride is needed to make 100.0 mL of a solution that is 0.500 M in chloride ion?

Chemistry
1 answer:
miss Akunina [59]3 years ago
3 0
M = n/V

.5M = n/.100 L

n = .1 L * .5M

n= .05 mols of MgCl2

mass of MgCl2 = .05 mols of MgCl2 * 95.211 grams/ 1 mol of MgCl2 

mass of MgCl2 = 4.76 grams

4.76 grams of MgCl2 is needed to make 100 ml of a solution that is .500M, in chloride ion. Bolded = confused
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