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3 years ago

What mass of magnesium chloride is needed to make 100.0 mL of a solution that is 0.500 M in chloride ion?

1 answer:

3 0

M = n/V

.5M = n/.100 L

n = .1 L * .5M

n= .05 mols of MgCl2

mass of MgCl2 = .05 mols of MgCl2 * 95.211 grams/ 1 mol of MgCl2

mass of MgCl2 = 4.76 grams

4.76 grams of MgCl2 is needed to make 100 ml of a solution that is .500M, in chloride ion. Bolded = confused

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Explanation:

For a:

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$Na_2CO_3(s)\rightarrow Na_2CO_3(aq.)$

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The chemical equation for the reaction of anion with water follows:

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Explanation :

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