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amm1812
3 years ago
10

2. What is the smallest unit of an organism that is classified as living? *

Chemistry
2 answers:
Leviafan [203]3 years ago
4 0

Answer:

D

Explanation:

The cell is the basic structural, functional and biological unit of all known living organisms. Cells are the smallest unit of life that is classified as a living thing, and are often called the "building blocks of life.

djyliett [7]3 years ago
3 0

Answer:

a cell

Explanation:

All living things are made of cells; the cell itself is the smallest fundamental unit of structure and function in living organisms.

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Which of the following characterizes an ionic bond?
velikii [3]

Answer:

option A

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3 years ago
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The sample of 15.0 g of KCl is dissolved into a solution with a total volume of 250.0 mL. What is the molarity of KCl in the sol
lina2011 [118]

Answer:

0.805 M.

Explanation:

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In this case, since the molarity of a solution is computing by dividing the moles of solute over the volume of solution in liters (M=n/V), for 15.0 g of potassium chloride (74.55 g/mol) we compute the corresponding moles:

n=15.0gKCl*\frac{1molKCl}{74.55gKCl}=0.201molKCl

Next, since the volume is 0.2500 in liters, the molarity turns out:

M=\frac{0.201mol}{0.2500L} \\\\M=0.805M

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3 0
3 years ago
FORENSIC SCIENCE HELP
Annette [7]
That is correct c
Explanation
7 0
3 years ago
A gas has a volume of 490. mL at a temperature of -35.0 degrees C. What volume would the gas occupy at 42.0 degrees Celsius? Ple
miskamm [114]

Answer:

648.5 mL

Explanation:

Here we will assume that the pressure of the gas is constant, since it is not given or specified.

Therefore, we can use Charle's law, which states that:

"For an ideal gas kept at constant pressure, the volume of the gas is proportional to its absolute temperature"

Mathematically:

\frac{V}{T}=const.

where

V is the volume of the gas

T is its absolute temperature

The equation can be rewritten as

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where in this problem we have:

V_1=490 mL is the initial volume of the gas

T_1=-35.0^{\circ} + 273 = 238 K is the initial temperature

T_2=42.0^{\circ}+273=315 K is the final temperature

Solving for V2, we find the final volume of the gas:

V_2=\frac{V_1 T_2}{T_1}=\frac{(490)(315)}{238}=648.5 mL

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3 years ago
Which of these is an indication that a chemical reaction has occurred?
nevsk [136]

Formation Of A Gas.

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3 years ago
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