The answer is "C" because the equator is closest to the sun, because the sun's rays hits the earth surface at the higher angel at the equator and also the sun is directly overhead the equator.
45✖️77 and then you will get your answer
Answer:
78.315 m/s²
Explanation:
Amplitude, A = 4.70 cm = 0.047 m
Frequency, f = 6.50 Hz
Angular frequency, ω = 2 π f = 2 x 3.14 x 6.50 = 40.82 rad/s
Maximum acceleration, a = ω² A
a = 40.82 x 40.82 x 0.047
a = 78.315 m/s²
Answer:
The acceleration of the snowball is 0.3125
Explanation:
The initial speed of the snowball up the hill, u = 0
The speed the snowball reaches, v = 5 m/s
The length of the hill, s = 40 m
The equation of motion of the snowball given the above parameters is therefore;
v² = u² + 2·a·s
Where;
a = The acceleration of the snowball
Plugging in the values, we have;
5² = 0² + 2 × a × 40
∴ 2 × 40 × a = 5² = 25
80 × a = 25
a = 25/80 = 5/16
a = The acceleration of the snowball = 5/16 m/s².
The acceleration of the snowball = 5/16 m/s² = 0.3125 m/s² .
