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hoa [83]
3 years ago
12

What is the temperature of a gas in which the atoms are moving very very slowly?

Physics
1 answer:
pickupchik [31]3 years ago
5 0
Cold.
Example: A frozen object (such as ice) is solid. Its molecules move extremely slow because the object itself isn't moving... It's like the skin on your bod... Imagine that wiggling and writhing on your bones. It's not like a gas, that can move freely and has no specific form or hold.
So again, the answer is Cold. 
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The change in position is known as
Goryan [66]

Answer:

distance or displacement

Explanation:

the answer can be displacement or displacement. if the required measure is between two points, we can call it as distance. but if we are to find the distance moved, we call it displacement. though it sounds pretty similar, they are very different. displacement is the shortest distance of movement of a body to its final point (or to the asked point) and distance is the total distance travelled by the body. and while distance is a scalar quantity, that this value shows the magnitude, displacement is a vector quantity, that this value should show both magnitude and direction.

for example if an object travels from point A to point B that is a 10 meters away and back, the distance will be 10+10 which is 20 meters. but the displacement is 0!

since not much information is given, the answer can be both distance or displacement

4 0
3 years ago
“All dogs bark. Fido barks. Thus, Fido is a dog,” is an example of which of the following?
nalin [4]
Deductive reasoning?
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3 years ago
List 3 different things you can read off a motion graph.
Lunna [17]

Answer:

1) Position time graph

2) Acceleration time graph

3) Velocity time graph

6 0
2 years ago
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What process is used to release energy in nuclear power plants
Anika [276]
.........Nucler fission.... .
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"What is the magnifying power of an astronomical telescope using a reflecting mirror whose radius of curvature is 5.9 m and an e
notka56 [123]

Answer:

The Magnifying power of a telescope is M = 109.26

Explanation:

Radius of curvature R = 5.9 m = 590 cm

focal length of objective f_{objective} = \frac{R}{2}

⇒ f_{objective} = \frac{590}{2}

⇒ f_{objective} = 295 cm

Focal length of eyepiece f_{eyepiece} = 2.7 cm

Magnifying power of a telescope is given by,

M = \frac{f_{objective} }{f_{eyepiece} }

M = \frac{295}{2.7}

M = 109.26

therefore the Magnifying power of a telescope is M = 109.26

4 0
3 years ago
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