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lara31 [8.8K]
3 years ago
12

A snowball starting at rest rolls down a hill and reaches 5 m/s. If the hill is

Physics
1 answer:
Lostsunrise [7]3 years ago
4 0

Answer:

The acceleration of the snowball is 0.3125

Explanation:

The initial speed of the snowball up the hill, u = 0

The speed the snowball reaches, v = 5 m/s

The length of the hill, s = 40 m

The equation of motion of the snowball given the above parameters is therefore;

v² = u² + 2·a·s

Where;

a = The acceleration of the snowball

Plugging in the values, we have;

5² = 0² + 2 × a × 40

∴ 2 ×  40 × a  = 5² = 25

80 × a = 25

a = 25/80 = 5/16

a = The acceleration of the snowball = 5/16 m/s².

The acceleration of the snowball = 5/16 m/s² = 0.3125 m/s² .

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A 6.0-kg box slides down an inclined plane that makes an angle of 39° with the horizontal. If the coefficient of kinetic frictio
jeka57 [31]

Answer:

a. 3.1 m/s^2

Explanation:

The equation of the forces along the directions parallel and perpendicular to the slope are:

- Along the parallel direction:

mg sin \theta - \mu_k R = ma

where :

m = 6.0 kg is the mass  of the box

g = 9.8 m/s^2 the acceleration of gravity

\theta=39^{\circ}  is the angle of the slope

\mu_k = 0.40 is the coefficient of friction

R is the normal reaction  

a is the acceleration

- Along the perpendicular direction:

R-mg cos \theta =0

From the 2nd equation, we get an expression for the reaction force:

R=mg cos \theta

And substituting into the 1st equation, we can find the acceleration:

mg sin \theta - \mu_k mg cos \theta = ma

Solving for a,

a=g sin \theta - \mu_k g cos \theta =(9.8)(sin 39^{\circ})-(0.40)(9.8)(cos 39^{\circ})=3.1 m/s^2

6 0
3 years ago
State the term using to describe the turning force force exerted by the man
defon

Answer:

The distance between the line of action of force and the axis of rotation (or pivoted point)

Explanation:

The distance between the line of action of force and the axis of rotation (or pivoted point) .

4 0
3 years ago
if it is known that the toggle clamp is a machine, what assumptions can be made about it? check all that apply. (you must provid
muminat

A toggle clamp is a device that you employ, often but not exclusively as part of a production process, to firmly place components or parts in place.

Explain about toggle clamp.

A toggle clamp's main characteristics are its rapid action and ability to be easily turned on and off by an operator. Toggle clamps also lock in place firmly. Because of this, toggle clamps are frequently employed in production lines where components need to be held firmly and quickly removed during routine manufacturing procedures.

Toggle clamps with standard or light action are often constructed from components of pressed steel that have been zinc-plated.

Depending on the setting in which you work, Stainless Steel is another alternative for Toggle Clamp production. Stainless steel toggle clamps are frequently used in regulated areas where hygiene is crucial, such as the food industry and the pharmaceutical business.

To know more about toggle clamps use link below:

brainly.com/question/20729246

#SPJ4

7 0
2 years ago
The student in item 1 moves the box up a ramp inclined at 12 degrees with the horizontal. If the box starts from rest at the bot
Alik [6]

Answer:

Acceleration up the ramp =  -2.745 m/s^{2}

Explanation:

Given

box is pulled at angle Θ = 25^{o}

Force applied F = 185N

coefficient of friction, μ_{k} = 0.27

mass of the box m = 35 kg

We know that,

acceleration due to gravity g = 9.8 m/s^{2}

horizontal component F_{x} = F cosΘ = 185 * cos25^{o} =167.67

vertical component F_{y} = F sinΘ =185*sin25^{o} = 78.18

Another vertical component is due to gravity F_{g} , force in given by

F_{g} = mg

    = 35 x 9.8

    = 343.35 N

Normal force F_{n} = F_{g}  - F_{y}

                            = 343.35 - 78.18

                            = 265.17 N

Frictional force F_{k} = F_{n} * μ_{k}

                               = 265.17 * 0.27

                               = 71.596 N

To find acceleration, we know that,

force = mass x acceleration

acceleration = \frac{force}{mass}

Here force is the summation of frictional force and horizontal component of the applied force. These force act in opposite directions.

force =  F_{k} - F_{x}

         = 71.596 - 167.67

         = -96.074

acceleration = \frac{-96.074}{35}

                     = -2.745 m/s^{2}

6 0
3 years ago
...............................................................
yuradex [85]

Answer:

true

Explanation:

when a ray of light travels from a less denser medium to a denser medium it tends to bend towards the normal.

5 0
2 years ago
Read 2 more answers
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