Question

I really need help on this question!

Answer 1

Use this formula which is th opposite of the formula used to find absorbance when you have the %T

(10^(-A))×100
where A=absorbance so
(10^(-0.85))×100

Answer 2

Answer:

14.12% the percent light transmitted through the colored sample at this collected wavelength.

Explanation:

Formula used to convert absorbance into transmittance is:

$A=\log \frac{I_o}{I}=-\log[T]$

$T=\frac{I}{I_o}$

where,

A = absorbance of solution

T = Transmittance

$I_o$ = incident light

$I$ = transmitted light

Given = A = 0.85

$0.85=-\log[T]$

$T=0.1412$

$0.1412=\frac{I}{I_o}$

$I=0.1412\times I_o$

Percentage of light transmitted to color solution:

$\frac{I}{I_o}\times 100=\frac{0.1412\times I_o}{I_o}\times 100=14.12\%$

14.12% the percent light transmitted through the colored sample at this collected wavelength.