Question

The pizza has an area of 78.5 in². What is the minimum width of a placemat that can be placed underneath it so that the pizza does not touch the table? Use 3.14 for pi.

Answer 1

Answer:

  10 in

Step-by-step explanation:

This problem bothers on the mensuration of flat shapes, circles and square.

we know that the pizza has a  circular profile

and the place-mat has a square profile.

Step one:

let us solve for the radius of the pizza

$area-of- pizzza= \pi r^2\\\\ 78.5= 3.142*r^2\\\\r^2= 78.5/3.142\\\\r^2= 24.98\\\\r= \sqrt{24.98} \\\\r=4.998\\\\r= 5 in$

Step two:

from inspection we know that the width of the place-mat is same as the diameter of the pizza

hence diameter of pizza

= 2r

=2*5

=10 in