Answer:
Option c. Neutral
Explanation:
Only neutral solution gives a green colouration to a pH paper
Compounds in order of increasing acidity will be written as d<c<b<a.
<h3>What is acidity?</h3>
The quantity of hydroxyl ions that a basic molecule may create in an aqueous solution is what is known as the acidity of bases. The quantity of hydronium ions that a substance may create in an aqueous solution determines how basic an acid is.
a, b are more acidic than c and d because of OH group attached to sp2 hybridised carbon which provide resonance stability for conjugate base
in c f has -I effect which increases acidity in a, NO2 has -m effect which increases acidity so increasing order is d<c<b<a
that is cyclohexanol < 2,4-difluorocyclohexanol < phenol < 2,4-dinitrophenol
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Well uncontrolled cell division can lead to cancer.
Answer:
0.0159m
Explanation:
9 M
Explanation:
Lead(II) chloride,
PbCl
2
, is an insoluble ionic compound, which means that it does not dissociate completely in lead(II) cations and chloride anions when placed in aqueous solution.
Instead of dissociating completely, an equilibrium rection governed by the solubility product constant,
K
sp
, will be established between the solid lead(II) chloride and the dissolved ions.
PbCl
2(s]
⇌
Pb
2
+
(aq]
+
2
Cl
−
(aq]
Now, the molar solubility of the compound,
s
, represents the number of moles of lead(II) chloride that will dissolve in aqueous solution at a particular temperature.
Notice that every mole of lead(II) chloride will produce
1
mole of lead(II) cations and
2
moles of chloride anions. Use an ICE table to find the molar solubility of the solid
PbCl
2(s]
⇌
Pb
2
+
(aq]
+
2
Cl
−
(aq]
I
−
0
0
C
x
−
(+s)
(
+
2
s
)
E
x
−
s
2
s
By definition, the solubility product constant will be equal to
K
sp
=
[
Pb
2
+
]
⋅
[
Cl
−
]
2
K
sp
=
s
⋅
(
2
s
)
2
=
s
3
This means that the molar solubility of lead(II) chloride will be
4
s
3
=
1.6
⋅
10
−
5
⇒
s
= √
1.6
4
⋅
10
−
5 =
0.0159 M
Answer:
Solutions with low pH have a sour taste.
Explanation: