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Dafna1 [17]
3 years ago
5

How many atoms are in 3.4 moles of iron

Chemistry
1 answer:
nikitadnepr [17]3 years ago
4 0
<h3>Answer:</h3>

2.047 × 10^24 atoms

<h3>Explanation:</h3>
  • We need to know that 1 mole of an element contains atoms equivalent to the Avogadro's constant.
  • The Avogadro's constant is 6.022 × 10^23.
  • Therefore, 1 mole of Fe contains 6.022 × 10^23 atoms.

In this case we are given 3.4 moles of Iron.

we are required to find the number of atoms in 3.4 moles.

Therefore, since 1 mole of Fe contains 6.022 × 10^23 atoms.

Then, 3.4 mole will contain;

= 3.4 moles × 6.022 × 10^23 atoms/mole

= 2.047 × 10^24 atoms

Thus, 3.4 moles of Iron contains 2.047 × 10^24 atoms

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Based on table N of the reference tables what is the number of hours required for 42k (potassium -42) to undergo three half-life
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The number of hours required : 37.2 hours

<h3>Further explanation</h3>

Given

⁴²K (potassium -42)

Required

The number of hours

Solution

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Usually, radioactive elements have an unstable atomic nucleus.  

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For three half-life periods :

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