All categories

3 years ago

2. In the equation 5(x - 3) = 25, what should you do after using the Distributive Property?

Mathematics

2 answers:

son4ous [18]3 years ago

7 0

Answer:

umm... This how I learned from the chapter simple equation. Hopefully helps

Step-by-step explanation:

5(x - 3) = 25 we have to find the value of 'x'

so transpose 5 x to the other side = (x - 3) = 25 divided by 5 becuz it was multiplication on the other side so it is equal to = (x - 3) = 5

Now we transpose -3 which is equal to = x = 5 + 3 = 8

so, x = 8

hopefully it helps!!!!!!!

Tanya [424]3 years ago

4 0

Step-by-step explanation:

first use distributive property

like this 5(x-3)=25

5x-15=25

then 5x=25+15

5x=40

5x/5=40/5

x=8

You might be interested in

Find the distance between a point (– 2, 3 – 4) and its image on the plane x+y+z=3 measured across a line (x + 2)/3 = (2y + 3)/4

dimaraw [331]

Answer:

Distance of the point from its image = 8.56 units

Step-by-step explanation:

Given,

Co-ordinates of point is (-2, 3,-4)

Let's say

$x_1\ =\ -2$

$y_1\ =\ 3$

$z_1\ =\ -4$

Distance is measure across the line

$\dfrac{x+2}{3}\ =\ \dfrac{2y+3}{4}\ =\ \dfrac{3z+4}{5}$

So, we can write

$\dfrac{x-x_1+2}{3}\ =\ \dfrac{2(y-y_1)+3}{4}\ =\ \dfrac{3(z-z_1)+4}{5}\ =\ k$

$=>\ \dfrac{x-(-2)+2}{3}\ =\ \dfrac{2(y-3)+3}{4}\ =\ \dfrac{3(z-(-4))+4}{5}\ =\ k$

$=>\ \dfrac{x+4}{3}\ =\ \dfrac{2y-3}{4}\ =\ \dfrac{3z+16}{5}\ =\ k$

$=>\ x\ =\ 3k-4,\ y\ =\ \dfrac{4k+3}{2},\ z\ =\ \dfrac{5k-16}{3}$

Since, the equation of plane is given by

x+y+z=3

The point which intersect the point will satisfy the equation of plane.

So, we can write

$3k-4+\dfrac{4k+3}{2}+\dfrac{5k-16}{3}\ =\ 3$

$=>6(3k-4)+3(4k+3)+2(5k-16)\ =\ 18$

$=>18k-24+12k+9+10k-32\ =\ 18$

$=>\ k\ =\dfrac{13}{8}$

So,

$x\ =\ 3k-4$

$=\ 3\times \dfrac{13}{8}-4$

$=\ \dfrac{7}{4}$

$y\ =\ \dfrac{4k+3}{2}$

$=\ \dfrac{4\times \dfrac{13}{8}+3}{2}$

$=\ \dfrac{19}{4}$

$z\ =\ \dfrac{5k-16}{3}$

$=\ \dfrac{5\times \dfrac{13}{8}-16}{3}$

$=\ \dfrac{-21}{8}$

Now, the distance of point from the plane is given by,

$d\ =\ \sqrt{(x-x_1)^2+(y-y_1)^2+(z-z_1)^2}$

$=\ \sqrt{(-2-\dfrac{7}{4})^2+(3-\dfrac{19}{4})^2+(-4+\dfrac{21}{8})^2}$

$=\ \sqrt{(\dfrac{-15}{4})^2+(\dfrac{-7}{4})^2+(\dfrac{9}{8})^2}$

$=\ \sqrt{\dfrac{225}{16}+\dfrac{49}{16}+\dfrac{81}{64}}$

$=\ \sqrt{\dfrac{1177}{64}}$

$=\ 4.28$

So, the distance of the point from its image can be given by,

D = 2d = 2 x 4.28

= 8.56 unit

So, the distance of a point from it's image is 8.56 units.

4 0

3 years ago

Four times a difference of 17 and a number is 84.

hichkok12 [17]

4×17-x=84
68-x=84
-x=16
x=-16

5 0

3 years ago

Adult red wolves vary in length from 137.16 cm to 168.64 cm. Estimate the difference in length between the longest and shortest

zhannawk [14.2K]

Answer:

As per the statement:

Adult red wolves vary in length from 137.16 cm to 168.64 cm.

To find the difference in length between the longest and shortest of these wolves.

Longest length of wolves = 168.64 cm

Shortest length of wolves= 137.16 cm

Then;

$\text{Difference of the length between the longest and shortest of these wolves}$ = $\text{Length of longest wolves} -\text{Length of shortest wolves}$

Substitute the given values we have;

$\text{Difference of the length between the longest and shortest of these wolves}$ = 168.64 - 137.16 = 31.48 cm

therefore, the difference in length between the longest and shortest of these wolves is 31.48 cm

3 0

3 years ago

Trey has plastic cubes stored in a box that measures

Sladkaya [172]

Your answer is D.160

5 0

3 years ago

Read 2 more answers

Find the area of the figure.

andrezito [222]

Answer:

area of figure = area of rectangle + area of triangle

area of rectangle= length × width

6×4

24yd²

area of triangle= 1/2×base×height

1/2×3×4

3×2

=6yd²

area of figure= 24+6

= 30yd²

7 0

3 years ago

2. In the equation 5(x - 3) = 25, what should you do after using the Distributive Property?​

2. In the equation 5(x - 3) = 25, what should you do after using the Distributive Property?