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telo118 [61]
3 years ago
8

Which of the following are decomposition reactions? *

Chemistry
1 answer:
zhuklara [117]3 years ago
3 0

Answer:

4

Explanation:

Starts with a compound and breaks down.

- Hope that helped! Please let me know if you need a further explanation.

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Hat is used and produced in glycoloysis?
agasfer [191]

During glycolysis is used glucose, ADP and pyruvate and produce ATP, water and NADH.

<h3>What is glycolysis?</h3>

Glycolysis is the first step of cellular respiration by which glucose is used to generate energy in the form of ATP.

Cellular respiration has three sequential steps, i.e., glycolysis, the Krebs cycle and oxidative phosphorylation.

Glycolysis is the cellular respiration step that generates 2 net high energy ATP molecules and 2 reduced NADH.

In conclusion, glycolysis uses glucose, pyruvate and ADP to generate ATP, water and Nicotinamide adenine dinucleotides (NADH).

Learn more about glycolysis here:

brainly.com/question/737320

#SPJ1

5 0
2 years ago
Which answer provides the correct name for the following hydrocarbon?
ivanzaharov [21]
1) Hydrocarbon: CH3 - CH2 - CH2 - CH2 - CH3

2) Only single bonds => alkane => sufix ane

3) no substitutions

4) 5 carbons = > prefix penta.

Therefore, the name is pentane.
4 0
4 years ago
Read 2 more answers
Please help<br>What is the possible ions of vanadium?
svetlana [45]

V+5, V+4, V+3, and V+2

7 0
4 years ago
"A crosslinked copolymer consists of 57 wt% ethylene (C2H4) repeat units and 43 wt% propylene (C3H6) repeat units. Determine the
ch4aika [34]

Explanation:

Percentage ethylene by weight = 57%

Percentage propylene by weight = 43%

Suppose in 100 grams of polymer:

Mass of ethylene = 57 g

Mass of propylene = 43 g

Moles of ethylene = \frac{57 g}{28 g/mol}=2.036 mol

Moles of propylene = \frac{43g}{42g/mol}=1.024 mol

1 mole = N_A =6.022\times 10^{23} molecules/ atoms

Units of ethylene = 2.036 mol\times N_A

Units of propylene = 1.024 mol\times N_A

a) Fraction of ethylene units:

=\frac{2.036 mol\times N_A}{2.306 mol\times N_A+1.024 mol\times N_A}=\frac{509}{765}

b ) Fraction of propylene units:

=\frac{1.024mol\times N_A}{2.306 mol\times N_A+1.024 mol\times N_A}=\frac{256}{765}

3 0
3 years ago
Calculate the equilibrium constant K for the following reaction: H2(g) +
SIZIF [17.4K]

Answer:

192.9

Explanation:

From the question,

Ke = [HCL]²/[H₂][CL₂].......................... Equation 1

Where Ke = Equilibrium constant.

Given: [HCL] = 0.0625 M, [H₂] = 0.0045 M, [CL₂] = 0.0045 M

Substitute these values into equation 1

Ke = (0.0625)²/(0.0045)(0.0045)

ke = (3.90625×10⁻³)/(2.025×10⁻⁵)

ke = 1.929×10²

ke = 192.9

Hence the equilibrium constant of the system = 192.9

5 0
3 years ago
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