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sineoko [7]
3 years ago
7

What is the maximum number of electrons in the following energy level? n = 2

Chemistry
2 answers:
Alisiya [41]3 years ago
7 0

Answer:

8

Explanation: I did the lesson

Citrus2011 [14]3 years ago
6 0
The answer is 18 electrons
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Alecsey [184]

Answer:

blood

Explanation:

D

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3 years ago
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The temperature of a star is 6000K and its luminosity is 1000. Which type of star is it?
Lorico [155]

Answer:

Its probably none of those.

Explanation:

White dwarf temperatures can exceed 100,000 Kelvin according to NASA (that's about 179,500 degrees Fahrenheit). Despite these sweltering temperatures, white dwarfs have a low luminosity as they're so small in size according to NMSU.

4 0
2 years ago
An amphoteric species is neither an acid nor a base. True or False
umka2103 [35]

Answer: False

Explanation: just took on edge

8 0
3 years ago
Identify the base-conjugate acid pair in this balanced equation:
Elan Coil [88]
<h3><u>Answer;</u></h3>

NH3/NH4+

<h3><u>Explanation;</u></h3>

From the equation;

NH3(aq)+HNO3(aq)→NH4+(aq)+NO3−(aq)  

NH3 is the base; while NH4+ is the conjugate acid  

HNO3 is the acid; while NO3- is the conjugate base  

  • The conjugate base of a Brønsted-Lowry acid is species that is formed after an acid donates a proton while the conjugate acid of a Brønsted-Lowry base is the species formed after a base accepts a proton.
3 0
3 years ago
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A certain radioactive nuclide has a half life of 1.00 hour(s). Calculate the rate constant for this nuclide. s-1 Calculate the d
Karo-lina-s [1.5K]

Answer:

k= 1.925×10^-4 s^-1

1.2 ×10^20 atoms/s

Explanation:

From the information provided;

t1/2=Half life= 1.00 hour or 3600 seconds

Then;

t1/2= 0.693/k

Where k= rate constant

k= 0.693/t1/2 = 0.693/3600

k= 1.925×10^-4 s^-1

Since 1 mole of the nuclide contains 6.02×10^23 atoms

Rate of decay= rate constant × number of atoms

Rate of decay = 1.925×10^-4 s^-1 ×6.02×10^23 atoms

Rate of decay= 1.2 ×10^20 atoms/s

8 0
3 years ago
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