What is the maximum number of electrons in the following energy level? n = 2

How was the structure of the atom discovered

Gennadij [26K]

Answer:

read down below

Explanation:

Building on the Curies' work, the British physicist Ernest Rutherford (1871–1937) performed decisive experiments that led to the modern view of the structure of the atom. ... Because it was the first kind of radiation to be discovered, Rutherford called these substances α particles.

4 0

3 years ago

A reaction where Oxygen is a reactant.

Goryan [66]

Answer:

chemical

Explanation:

6 0

3 years ago

Read 2 more answers

The chemical symbols of hydrogen, calcium and chlorine are:

jeka57 [31]

Answer:

H, Ca, Cl is the answer dude

3 0

3 years ago

Read 2 more answers

A. Calculations for the Determination of Ammonium Chloride The data from the data entry portion of the report has been copied in

Vladimir79 [104]

Answer:

A

Explanation:

Considering question A

Mass of original sample is $m_o = 0.945 \ g$

Mass of NH4Cl is $m_n = 0.116 \ g$

Percent of NH4Cl is $k = 12.275 \%$

B

Mass of NaCl $m_k = 0.359 \ g$

C

Mass of SiO2 $m_e = 0.46$

D

Mass of original sample $m_o = 0.945 \ g$

Differences in these weights (g) (use the absolute value of the difference)

recovery of matter $G = 0.01 \ g$

The correct option is C

From the question we are told that

The mass of evaporating dish on #1 is $m_1 = 38.646 \ g$

The mass of evaporating dish and original sample $m_2 = 39 591 \ g$

The mass of evaporating dish after subliming $NH_4Cl$ is $m_3 = 39.4750 \ g$

Generally the mass of the original sample is mathematically represented as

$m_o = m_2 - m_1$

=> $m_o = 39 591 - 38.646$

=> $m_o = 0.945 \ g$

Generally the mass of $NH_4Cl$ is mathematically represented as

$m_n = m_2 - m_3$

=> $m_n = 39 591 - 39.4750$

=> $m_n = 0.116 \ g$

The Percent $NaH_4 Cl (g)$

$k = \frac{ m_n}{m_o} *100$

=> $k = \frac{0.116 }{0.945} *100$

=> $k = 12.275 \%$

Considering question B

The mass of evaporating dish #2 is $m_g = 38700\ g$

The mass of watch glass is $m_a = 28 299 \ g$

The mass of evaporating dish #2, watch glass and NaCl $m_b = 67,355 \ g$

Generally the mass of NaCl is

$m_k = m_b -[m_g + m_a]$

=> $m_k = 67,355 -[38700 + 28 299]$

=> $m_k = 0.359 \ g$

Considering question C

The mass of evaporating dish is $m_p= 38.645$

The mass of evaporating dish and SiO2 $m_s = 39.105 \ g$

Generally the mass of SiO2 is mathematically represented as

$m_e = 39.105 - 38.645$

=> $m_e = 0.46$

Considering D

The mass of the original sample is $m_o = 0.945 \ g$

Generally the experimental mass recovered (NH_4Cl,NaCl, SiO2 ) is mathematically evaluated as

$M =0.116 + 0.46 + 0.359$

$M = 0.935 \ g$

Generally the differences in these weights (g) of recovery of matter is mathematically represented as.

$G =0.945- 0.935$

=> $G = 0.01 \ g$

While drying the NaCl, the liquid boiled and some splattered out of the evaporating dish, causing the recovered mass to be lower.

6 0

3 years ago

One<br> 63 Cu atom has a mass of 1.045 x 10-22 g. Calculate the mass of 3.0 moles of 63Cu atoms

12345 [234]

The mass of 3.0 moles of ⁶³Cu atoms is 188.8 g

<h3>Stoichiometry</h3>

From the question, we are to calculate the mass of 3.0 moles of ⁶³Cu atoms.

From the given information,

One ⁶³Cu atom has a mass of 1.045 × 10⁻²² g

First, we will determine the number of atoms present in 3.0 moles of ⁶³Cu atoms

Using the formula,

Number of atoms = Number of moles × Avogadro's constant

Number of ⁶³Cu atoms present = 3.0 × 6.022 × 10²³

Number of ⁶³Cu atoms present = 18.066 × 10²³ atoms

Now, we will determine the mass of 18.066 × 10²³ ⁶³Cu atoms

If 1 ⁶³Cu atom has a mass of 1.045 × 10⁻²² g

Then,

18.066 × 10²³ ⁶³Cu atoms will have a mass of 18.066 × 10²³ × 1.045 × 10⁻²²

18.066 × 10²³ × 1.045 × 10⁻²² = 188.7897 g

≅ 188.8 g

Hence, the mass of 3.0 moles of ⁶³Cu atoms is 188.8 g

Learn more on Stoichiometry here: brainly.com/question/13654901

5 0

2 years ago