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3 years ago

Which of the following would increase the surface area of a solid so that it dissolves faster?

1 answer:

4 0

Increasing the surface area increases the rate of solubility of a solid because a larger number of molecules of the greater surface area have contact with the solvent

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A sample of Neon is in a sealed container held under isothermic conditions. The initial pressure and volume are 2.7 atm and 4.5

Marina CMI [18]

Answer:

The final volume in mL is 7.14 mL or 7.1 mL.

Explanation:

1.Use Boyle's Law( $P_{1} V_{1}= P_{2} V_{2}$ ). Re-arrange to solve for $V_{2}$ <em> for the final volume.</em>

<em />

<em>2. Plug in values. </em> $V_{2} =\frac{(2.7 atm)(4.5 mL)}{(1.7 atm)} = 7.14 mL$

3 0

2 years ago

What is the atomic number of a sodium atom that has 11 protons and 12 neutrons?

galben [10]

Answer should be 23.

3 0

3 years ago

How would you prepare 2.00 l of a 0.25 m acetate buffer at ph= 4.50 from concentrated acetic acid (17.4 m) and 1.00 m naoh? the

zvonat [6]

The reaction of acetic acid with sodium hydroxide is:

$CH_3COOH + NaOH CH_3COONa + H_2O$

The ratio of A-/HA is calculated as follows:

According to Henderson Hasslebach equation:

$[A-]/[HA] = 10^p^H^-^p^K^_a$

$= 10^4^.^7^6^-^4^.^5^ = ^2^.^1^8$

The total concentration of HA and A- = 2.0 L * 0.25 M = 0.5 mol.

$[ A- ]+ [ HA ]= 0.5$

$[ A^- ] = 0.5 – [ HA]$

[ HA] = 0.156 mol and [ A- ]= 0.343 mol

Total of 0.5 moles of acetic acid is required:

$0.5 mol HA * 60.0 g$

HA = 30.0 g acetic acid

Conversion of 0.343 moles of the acetic acid to acetate can be performed by adding NaOH

$0.343 mol HA * (1 mol NaOH/1 mol HA) * (1000 mL/1 mol NaOH)$

= 343 mL

Thus, 343 mL of 1M NaOH is required

3 0

3 years ago

You drink part of your bottle of water, leaving 160 g in the bottle. When you purchased the water, it had a temperature of 10oC.

Evgesh-ka [11]

The energy that the water in the bottle absorbed is obtained as 16800 J.

<h3>What is the specific heat capacity?</h3>

The specific heat capacity of the water refers to the energy that is required to raise the temperature of 1Kg of the water by 1 degree.

Now we have the following;

mass (m) = 160 g

temperature change dT = ( 35oC - 10oC)

specific heat capacity (c)= 4.2 J/(g * oC).

Now;

H = mcdT

H = 160 g * 4.2 J/(g * oC) * ( 35oC - 10oC)

H = 16800 J

Learn more about specific heat capacity:brainly.com/question/1747943

#SPJ1

7 0

2 years ago

Which of the following contains both ionic and covalent bonding?

bogdanovich [222]

My answer would be +3

4 0

3 years ago

Read 2 more answers