Answer:
092) Icosane
093) Ethene
Explanation:
092) The given compounds are;
Decane C₁₀H₂₂; Viscosity = 0.850 mPa·s (25°C)
Ethene C₂H₄ (gas); Viscocity ≈ 0.01038 m
Icosane C₂₀H₄₂; Solid at room temperature
Methane CH₄; gas at room temperature
The viscosity of the given carbon and hydrogen compounds is observed to increase with their molar masses
Therefore, icosane, which is a solid at room temperature, has the highest viscosity (resistance to deformation) out of the given compounds
093) Polymers are made from monomer alkene units, therefore, ethene, which is the only alkene among the given compounds can be used to produce a polymer
Polyethene is formed by the polymerization of ethene whereby molecules of ethene are joined together to form poly(ethene)
Answer:
The true statements are given below.
Explanation:
1 D glucose is a reducing sugar
2 The oxidation of reducing sugar forms a carboxylic acid sugar.
D glucose is a reducing sugar because glucose contain a free hydroxyl group (-OH)in its anomeric carbon.
The oxidation of reducing sugar result in the conversion of -CHO group in case of aldose sugar and -CH2OH group in case of ketose sugar into carboxylic acid(-COOH).
The correct number of significant figures gotten from the result of (329.5/0.45)-23.2 is infinite because there is no uncertain digit as a result of the answer being 709.022222222 when calculated.
<h3>What is a Significant figure?</h3>
These refers to the digits which contributes to the degree of accuracy of a value and is usually counted starting from the non zero digits. In cases where the zero is between other numbers it is regarded as being significant such as 70.0111 in which the number of significant figures is six.
The result gotten from the expression (329.5/0.45)-23.2 is 709.022222222 which has a recurring decimal thereby making it difficult to calculate the number of recurring decimal.
Therefore it has infinitely many significant figures because there is no uncertain digit.
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Answer:
1188.976 mmHg
Explanation:
Initial pressure P1= 755 mmHg
Initial volume V1 = 6.00 litres
Final volume V2 = 3.81 litres
Final pressure P2= the unknown
Now applying Boyle's Law,we have;
P1V1 = P2V2
Since P2 is the unknown then it has to be made the subject of the formula.
P2=P1V1/ V2
P2= 755 × 6.00/ 3.81
P2= 1188.976 mmHg
Therefore, the new pressure is; 1188.976 mmHg
Answer:
The same kind of coffee, the same coffee maker, the same amount and type of water, and the same electrical sources were used.
Explanation: