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Ket [755]
3 years ago
5

If an element has a half-life of 16.7 days, how many days to go from 1000 to 250 atoms?

Chemistry
1 answer:
lisabon 2012 [21]3 years ago
3 0

Answer:

The answer to your question is:

Explanation:

a)

Data

half-life = 16.7 days

go from 1000 to 250 atoms

                                1000

                                  500         1 half life

                                  250         2 half lives

                16.7 days ---------------- 1 half life

                 x             ----------------- 2 half lives

                x = (2 x 16.7) / 1

               x = 33.4 days        

               

b)

number of atoms = ?

after 9 half-lives

                            1000

                              500       1 half life

                               250       2 half lives

                               125        3 half lives

                                62.5     4 half lives

                               31.25     5 half lives

                                15.63    6 half lives

                                 7.81      7 half lives

                                 3.9       8 half lives

                                 1.95      9 half lives

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Sulfur dioxide has a vapor pressure of 462.7 mm Hg at –21.0 °C and a vapor pressure of 140.5 mm Hg at –44.0 °C. What is the enth
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Answer : The value of \Delta H_{vap} is 28.97 kJ/mol

Explanation :

To calculate \Delta H_{vap} of the reaction, we use clausius claypron equation, which is:

\ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

P_1 = vapor pressure at temperature -21.0^oC = 462.7 mmHg

P_2 = vapor pressure at temperature -44.0^oC = 140.5 mmHg

\Delta H_{vap} = Enthalpy of vaporization = ?

R = Gas constant = 8.314 J/mol K

T_1 = initial temperature = -21.0^oC=[-21.0+273]K=252K

T_2 = final temperature = 45^oC=[-41.0+273]K=232K

Putting values in above equation, we get:

\ln(\frac{140.5mmHg}{462.7mmHg})=\frac{\Delta H_{vap}}{8.314J/mol.K}[\frac{1}{252}-\frac{1}{232}]\\\\\Delta H_{vap}=28966.6J/mol=28.97kJ/mol

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What is the enthalpy of formation (?H?f) of NaHCO3(s) from its constituent elements.
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Answer:

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Explanation:

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From the value of the enthalpy of formation of NaHCO3, it shows that the reaction is exothermic, that is the formation of NaHCO3 from its constituents elements. As such, the heat content of the reactants is greater than the products.

The step by step explanation is shown in the attachment.

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