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WITCHER [35]
3 years ago
7

Which of the following will increase the volume of a gas?

Chemistry
1 answer:
Dmitry_Shevchenko [17]3 years ago
7 0

Answer:

B. Decreasing the pressure applied to the gas molecules

Explanation:

According to Boyle's Law, the pressure of the gas is inversely proportional to the volume of the gas. So, the option B is correctly implied to it.

Other values such as Temperature, Number of molecules are inversely proportional to the volume of the gas.

Size of the gas molecules is negligible as compared to volume.

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Use the information provided to determine ΔH°rxn for the following reaction: ΔH°f (kJ/mol) 3 Fe2O3(s) + CO(g) → 2 Fe3O4(s) + CO2
zepelin [54]

Answer:

ΔH°rxn = -47 kJ

Explanation:

Using Hess´s law for the reaction:

3 Fe2O3(s) + CO(g) → 2 Fe3O4(s) + CO2(g) ,

the ΔH°rxn will be given by the expression:

ΔH°rxn kJ  =   2ΔHºf(Fe3O4)  + ΔHºf(CO2)   - ( 3ΔHºf(Fe2O3) + ΔHºf(CO) )

=  2(-1118) + (-394) - ( 3( -824 ) + ( -111 ) )

= - 47 kJ

3 0
3 years ago
Read 2 more answers
How do compounds differ from their component elements? A. Compounds have different numbers of neutrons than their component elem
Rudiy27
The correct answer is C. Compounds have different properties than their component elements. When compounds are formed, they undergo change resulting to changes in the properties they exhibit. It will have its new set of properties different from the elements.
6 0
3 years ago
With radiocarbon dating, scientists compare an object's carbon-14 levels with _____. the carbon-14 levels of an object from the
trapecia [35]

Answer:carbon-14 levels in the atmosphere

Explanation:

When carrying out radiocarbon dating, the level of carbon-14 in a sample is compared with the level of carbon 14 in the atmosphere because, objects exchange carbon-14 with the atmosphere.

Comparison of the activities of carbon-14 in the atmosphere and in the sample gives the age of the sample since the half-life of carbon-14 is a constant.

5 0
3 years ago
If the atmospheric pressure is 0.975 atm what is the pressure of the enclosed gas
Nuetrik [128]
Missing in your question:
Picture (1)
when its an open- tube manometer and the h = 52 cm. 
when the pressure of the atmosphere is equal the pressure of the gas plus the pressure from the mercury column 52 Cm so, we can get the pressure of the gas from this formula:
P(atm) = P(gas) + height (Hg)
∴P(gas) = P(atm) - height (Hg)
              = 0.975 - (520/760) 
              = 0.29 atm
Note: I have divided 520 mm Hg by 760 to convert it to atm
Picture (2)
The pressure of the gas is the pressure experts by the column of mercury and when we have the Height (Hg)= 67mm 
So the pressure of the gas =P(atm) + Height (Hg)
                                             =  0.975 + (67/ 760) = 1.06 atm
Picture (3) 
As the tube is closed SO here the pressure of the gas is equal the height of the mercury column, and when we have the height (Hg) = 103 mm. so, we can get the P(gas) from this formula:
P(gas) = Height(Hg)
           = (103/760) = 0.136 atm

6 0
3 years ago
Write a conclusion statement that addresses the following questions:
Sindrei [870]

Answer:

did you ever get the answer lol

6 0
3 years ago
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