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WITCHER [35]
3 years ago
7

Which of the following will increase the volume of a gas?

Chemistry
1 answer:
Dmitry_Shevchenko [17]3 years ago
7 0

Answer:

B. Decreasing the pressure applied to the gas molecules

Explanation:

According to Boyle's Law, the pressure of the gas is inversely proportional to the volume of the gas. So, the option B is correctly implied to it.

Other values such as Temperature, Number of molecules are inversely proportional to the volume of the gas.

Size of the gas molecules is negligible as compared to volume.

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<h3>What superconducting material works with the highest temperature?</h3>

As of 2020, the material with the highest accepted superconducting temperature is an extremely pressurized carbonaceous sulfur hydride with a critical transition temperature of +15°C at 267 GPa.

<h3>How do high-temperature superconductors work?</h3>

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6 0
2 years ago
Why do polar substances dissolve in water?
77julia77 [94]

water molecules are attracted to polar molecules and surround them.
7 0
3 years ago
Read 2 more answers
The periodic table is based on an element's
patriot [66]
The elements atomic number, the number of protons in the necules
6 0
3 years ago
If 72.1 mL of 0.543 M H2SO4 completely titrates 39.0 mL of KOH solution, what is the molarity of the KOH solution? a. 0.317 M b.
Snezhnost [94]

<u>Answer:</u> The correct answer is Option  d.

<u>Explanation:</u>

To calculate the molarity of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH

We are given:

n_1=2\\M_1=0.543M\\V_1=72.1mL\\n_2=1\\M_2=?M\\V_2=39.0mL

Putting values in above equation, we get:

2\times 0.543\times 72.1=1\times M_2\times 39.0\\\\M_2=2.01M

Hence, the correct answer is Option d.

4 0
3 years ago
Consider the following first-order reaction: A → B. The concentration of A at the start of the reaction is 4.17 M and after 4.84
valina [46]

Answer : The value of rate constant is, 0.0327s^{-1}

Explanation :

First we have to calculate the rate constant, we use the formula :

Expression for rate law for first order kinetics is given by:

k=\frac{2.303}{t}\log\frac{a}{a-x}

where,

k = rate constant  = ?

t = time passed by the sample  = 4.84 s

a = initial concentration = 4.17 M

a - x = concentration after time 4.84 s = 3.56 M

Now put all the given values in above equation, we get

k=\frac{2.303}{4.84}\log\frac{4.17}{3.56}

k=0.0327s^{-1}

Therefore, the value of rate constant is, 0.0327s^{-1}

4 0
3 years ago
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